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3 years ago

5

$1675 at 4.6% for 4 years whats the interest earned and balance amount

1 answer:

nignag [31]3 years ago

7 0

If simple interest is paid:
Interest=Pit = 1675*0.046*4=308.20

If compounded annually
Interest=P[(1+i)^t-1]=1675*(1.046^4-1)=330.13

If compounded monthly
Interest=P[(1+i/12)^(t*12)-1]=1675*((1+0.046/12)^(4*12)-1)=337.67

Please be sure to specify the type of interest and compounding period if it is compound interest.

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Simplify the expression.<br><br> (−0.75x + 8) + (1.5x + 4.4)<br><br> The simplified expression is

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Collect like terms

(-0.75x + 1.5x) + (8 + 4.4)

Simplify

<u>0.75x + 12.4 </u>

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3 years ago

What is the square root of 49 if it is then multiplied by 14 and divided by pi?

AlekseyPX

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Solve the inequality. <br><br>The solution is....

MAVERICK [17]

Answer:

Step-by-step explanation:

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3 years ago

Find the area, in square feet, of a triangle whose base is 42⁄3 feet and whose altitude is 84⁄7 feet. A. 135⁄21 B. 20 C. 40 D. 2

CaHeK987 [17]

Answer:

Option B. $20\ ft^{2}$

Step-by-step explanation:

we know that

The area of a triangle is equal to

$A=\frac{1}{2}bh$

we have

$b=4\frac{2}{3}\ ft$

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$h=8\frac{4}{7}\ ft=\frac{8*7+4}{7}=\frac{60}{7}\ ft$

substitute the values

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3 years ago

Read 2 more answers

A radiator contains 10 quarts of fluid, 30% of which is antifreeze. How much fluid should be drained and replaced with pure anti

babymother [125]

Answer:

1 3/7 quarts should be drained off and replaced with pure antifreeze.

1 3/7 ≈ 1.4286

Current amount of antifreeze in quarts is -

30/ 100 × 10 = 3

40% ---> 4 quarts

Let the amount drained of and replaced with antifreeze be x-

The amount left after draining off is 10 − x.

The amount of antifreeze is 30/ 100 (10−x).

30/100(10-x)+x=4

3-3/10x+x=4

3+x(1-3/10)=4

x=1*10/7=1 3/7 quarts

check;

10- 1 3/7 = 8 4/7

=(30/100*8 4/7)+1 3/7

=(3/10 * 60/7) + 10/7

=3*6/7 + 10/7

=28/7

=4

4 liters of pure antifreeze is mixed into 10 quarts.

8 0

3 years ago