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slavikrds [6]
3 years ago
10

If f(3)=2x^3 -2 , what is the value of f(2)

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0

I'm not sure about this but will give it a try:

Let f(n) = 2xⁿ - 2

Then f(3) = 2x³ - 2

So, f(2) = 2x² - 2

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Answer:

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Step-by-step explanation:

The midpoint formula is:

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Let (5,6) be x₁ and y₁ and let's let (9,2) be x₂ and y₂. Thus, the midpoint is:

M=(\frac{5+9}{2},\frac{6+2}{2})

Add:

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Divide by 2:

M=(7,4)

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