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iren2701 [21]
3 years ago
7

8x+4(x-3)=4(6x+4)-4 please help

Mathematics
1 answer:
kvasek [131]3 years ago
5 0

Answer:

x = -2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

8x + 4(x - 3) = 4(6x + ) -4

8x +(4)(x) + (4)(-3) = (4)(6x) + (4)(4) + -4 (distribute)

8x + 4x + -12 = 24x + 16 + -4

(8x) + (4x) +(-12) = (24x) + (16 + -4) (combine like terms)

12x + -12 = 24x + 12

12x -12 = 24x + 12

Step 2: Subtract 24x from both sides.

12x -12 -24x = 24x + 12 -24x

-12x -12 = 12

Step 3: Add 12 to both sides.

-12x - 12 + 12 = 12 + 12

-12x = 24

Step 4: Divide both sides by -12.

-12x/-12 = 24/-12   <u>x = -2</u>  

HOPE THIS HELPED!!!

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2. c = 47,000 × n, where c is the cost of n number of bears.

3. a) The cost to ride 5 rides = $20.50, the cost to ride 8 rides = $28.00

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b) The cost to ride 12 rides = $36.00.

Step-by-step explanation:

Step 1; To find the cost of one bear, we divide the cost of bears by the number.

If 4 bears cost $188,000, 1 bear costs = \frac{188000}{4} = $47,000.

If 7 bears cost $329,000, 1 bear costs = \frac{329,000}{7} = $47,000.

So the equation is c = 47,000 × n, where c is the cost to buy n bears.

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When the number of rides is 8, C(8) = 15.50 + 2.50 (8-3) = 15.50 + 2.50 (5) = 15.50 + 12.50 = $28.00.

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Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

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  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

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  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

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Hence:

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0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

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