the length of a rectangle is 4 feet longer than twice the width of the same rectangle. if the perimeter of the rectangle is 68 f
eet, what are the dimension ( the length and width) of the rectangle?
1 answer:
Represent the length and width by L and W. Then L = W + 4.
Using the perimeter formula: P = 2L + 2W = 68 ft = 2W) + 2(W+4).
Solve for W: 68 = 2W + 2W + 8, or 4W = 60. Thus, W = 15 and L = 19.
The dimensions of the rectangle are 15 by 19 feet.
You might be interested in
Y-5=4(x+2)
y-5=4x+8
+5 +5
y=4x+13
is that what you are talking about?
Answer:
5.96666666667
Step-by-step explanation:
I used a calculator
Step-by-step explanation:
F(x) = 1/9 - 9
= (1-81)/9
=-80/9
...............................
Plzz mark it as a brilliant answer
Answer:
y = 4
Step-by-step explanation:
distribute
10 + 2y = 18
minus 10 from both sides
2y = 8
divide by 2
y = 4
Its 9m-9(2) make sure to think of the minus sign as a negative because it will equal 9m-18 not 9m+18
