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N76 [4]
3 years ago
5

Can you please show me how to do this problem. (I will mark Brainliest)

Mathematics
1 answer:
Kisachek [45]3 years ago
4 0

Answer:

Sin A = 0.6896

Cos A = 0.7241

Tan A = 0.9524

Step-by-step explanation:

Using SOH-CAH-TOA

Sin A = Opposite / Hypotenous

         = 20 / 29

         = 0.6896

Cos A = Adjacent / Hypotenous

          = 21 / 29

         = 0.7241

Tan A = Opposite / Adjacent

          = 20 / 21

          = 0.9524

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8000*.10(y)
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A ladder leaning against a building makes an angle of 65 degrees with the ground and reaches a point on the building 20 feet abo
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22 feet. Using the sine rule theory: 20/sin(65)=x/sin(90). You know that it's 90 degrees because you assume the ground and the building make a 90 degree angle. So, you cross multiply and get 20sin(90)/xsin(65) and solve for x.
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A library subscribes to two different weekly news magazines, each of which is supposed to arrive in Wednesday�s mail. In actuali
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Answer:

P(Y = 0) = 0.09

P(Y = 1) = 0.4

P(Y = 2) = 0.32

P(Y = 3) = 0.19

Step-by-step explanation:

Let the events be:

W = Wednesday

T = Thursday

F = Friday

S = Saturday

Their corresponding probabilities are

P(W) = 0.3\\P(T) = 0.4\\P(F) = 0.2\\P(S) = 0.1

Since Y = number of days beyond Wednesday that it takes for both magazines to arrive(so possible Y values are 0, 1, 2 or 3)

The possible number of outcomes are therefore 4^2 = 16\\(W, W), (W, T), (W, F), (W, S)\\(T, W), (T, T), (T, F), (T, S)\\(F, W), (F, T), (F, F), (F, S)\\(S, W), (S, T), (S, F), (S, S)

The values associated for each of the outcomes are as follows:

Y(W, W) = 0, Y(W, T) = 1, Y(W, F) = 2, Y(W, S) = 3\\Y(T, W) = 1, Y(T, T) = 1, Y(T, F) = 2, Y(T, S) = 3\\Y(F, W) = 2, Y(F, T) = 2, Y(F, F) = 2, Y(F, S) = 3\\Y(S, W) = 3, Y(S, T) = 3, Y(S, F) = 3, Y(S, S) = 3

The probability mass function of Y is,

P(Y = 0) = 0.3(0.3) = 0.09\\P(Y = 1) = P[(W, T) or (T, W) or (T, T)]\\= [0.3(0.4) + 0.3(0.4) + 0.4(0.4)]\\= 0.4\\\\P(Y = 2) = P[(W, F) or (T, F) or (F, W) or (F, T) or (F, F)]\\= [0.3(0.2) + 0.4(0.2) + 0.2(0.3) + 0.2(0.4) + 0.2(0.2)]\\= 0.32\\\\P(Y = 3) = P[(W, S) or (T, S) or (F, S) or (S, W) or (S, T) or (S, F) or (S, S)]\\= [0.3(0.1) + 0.4(0.1) + 0.2(0.1) + 0.1(0.3) 0.1(0.4) + 0.1(0.2) + 0.1(0.1)]\\= 0.19

7 0
3 years ago
A triangle with which angle types could be constructed?
kifflom [539]

Answer:

B is the answer.

Step-by-step explanation:

*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^

Triangles cannot have two 90 degrees because that would add up to 180 and triangles need 3 angles to add to 180

You can't have an obtuse angle and a right angle. say the obtuse angle was 110, and a right angle is 90. 110 + 90 is more than 180.

Two obtuse angles would be more than 180.

This leaves us with B being correct, because you can have an obtuse angle and an acute angle, and it can be less than 180 degrees.

*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*^

#teamtrees #WAP (Water And Plant)

5 0
2 years ago
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How much force was applied to a 5 kg object if it accelerated by 15 m/s/s
REY [17]

Answer:

We use Newton's second law of motion, which states that,

F

=

m

a

where:

F

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m

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a

is the acceleration of the object in meters per second squared

So, we get:

F

=

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2

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(

∵

1

N

≡

1

kg m/s

2

)

Step-by-step explanation:

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3 years ago
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