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3 years ago

Can you please show me how to do this problem. (I will mark Brainliest)

Mathematics

1 answer:

Kisachek [45]3 years ago

4 0

Answer:

Sin A = 0.6896

Cos A = 0.7241

Tan A = 0.9524

Step-by-step explanation:

Using SOH-CAH-TOA

Sin A = Opposite / Hypotenous

= 20 / 29

= 0.6896

Cos A = Adjacent / Hypotenous

= 21 / 29

= 0.7241

Tan A = Opposite / Adjacent

= 20 / 21

= 0.9524

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Alekssandra [29.7K]

13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0

Recall the double angle identity,

sin^2(x) = (1 - cos(2x))/2

If we let x = 13pi/12, then

sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]

where we took the negative square root because we expect a negative value.

Now, because cosine has a period of 2pi, we have

cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2

Then

sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]

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3 years ago

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Answer:

Step-by-step explanation:

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2 years ago

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kari74 [83]

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Step-by-step explanation:

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2 years ago

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Ivanshal [37]

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Step-by-step explanation: Given that boys and girls are equally likely.

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Since the events of having a boy and a girl are independent of each other, so

the probability of having 6th girl dose not depend on the birth of the first five girls.

We know that there are only two possible cases (either a boy or girl will born).

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3 years ago

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3 years ago