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Taya2010 [7]
3 years ago
9

Through(-2,-3); parallel to 3x+2y=5

Mathematics
2 answers:
Vilka [71]3 years ago
8 0

Step-by-step explanation:

Hey there!

<u>Firstly </u><u>find </u><u>slope </u><u>of</u><u> the</u><u> </u><u>given</u><u> equation</u><u>.</u>

Given eqaution is: 3x + 2y = 5.......(i)

Now;

slope(m1) =   \frac{ - coeff. \: of \: x}{coeff. \: of \: y}

or \: m1 =  \frac{ - 3}{2}

Therefore, slope (m1) = -3/2.

As per the condition of parallel lines,

Slope of the 1st eqaution (m1) = Slope of the 2nd eqaution (m2) = -3/2.

The point is; (-2,-3). From the above solution we know that the slope is (-3/2). So, the eqaution of a line which passes through the point (-2,-3) is;

(y-y1) = m2 (x-x1)

~ Keep all values.

(y + 3) =  \frac{ -  3}{2} (x + 2)

~ Simplify it.

2(y + 3)  = - 3x - 6

2y + 6 =  - 3x - 6

3x  + 2y + 12 = 0

Therefore, the eqaution of the line which passes through the point (-2,-3) and parallel to 3x + 2y= 5 is 3x + 2y +12 =0.

<em><u>Hope </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

kifflom [539]3 years ago
7 0
Hopefully it this helps.

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