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frosja888 [35]
3 years ago
10

Classify these functions as even, odd, or neither even nor odd.

Mathematics
1 answer:
Orlov [11]3 years ago
8 0

Answer:

  N, E, E, O, E

  O

Step-by-step explanation:

<u>f(x) = 4x³ -3x² +5</u> -- has both even and odd degree terms, so is Neither even nor odd

<u>f(x) = -7x² +1</u> -- has only even degree terms, so is Even

<u>y = cos(-x)</u> -- Cosine is an even function, so this is Even

<u>y = csc(x)</u> -- Cosecant is an odd function, so this is Odd

<u>y = tan(x)/x</u> -- both tan(x) and x are odd functions, so their ratio is Even

<u>y = sin(x)/cos(x)</u> -- = tan(x), an odd function, so is Odd

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2(x+1)=38 I would just like to check my answer for this problem. I think x equals 16. But I would like to clarify
astraxan [27]

There are two methods to do this:

1. 2(x + 1) = 38

2*x + 2*1 = 38 (Expand the bracket)

2x + 2 = 38

2x = 36 (Subtract 2 from both sides)

x = 18 (Divide each side by 2)

2. 2(x + 1) = 38

(x + 1) = 19 (Divide each side by 2)

x = 18 (Subtract 1 from each side)

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4 years ago
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Find the product of 20x9x5 using distributed property?
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20•9=180
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4 years ago
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horrorfan [7]

Answer:

the correct option is option c.

Step-by-step explanation:

We have the expression: (160*243)^1/5

First, we know that 160 = 5(2^5)

And, 243 = 3^5

Then we have: (160*243)^1/5 = [5(2^5)(3^5)]^1/5 = 6(5)^1/5

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In circle C, what is mFH?<br><br> 31°<br> 48°<br> 112°<br> 121°
natta225 [31]

we know that

The measurement of the external angle is the semi-difference of the arcs it comprises.

so

Step 1

<u>Find the measure of the arc AJ</u>

m∠BDE=\frac{1}{2} *[measure\ arc\ AJ-measure\ arc\ BE]

in this problem we have

m∠BDE=37\°

measure\ arc\ BE=38\°

substitute in the formula

37\°=\frac{1}{2} *[measure\ arc\ AJ-38\°]

74\°=[measure\ arc\ AJ-38\°]

measure\ arc\ AJ=74\°+38\°=112\°

Step 2

<u>Find the measure of the arc FH</u>

m∠FGH=\frac{1}{2} *[measure\ arc\ AJ-measure\ arc\ FH]

in this problem we have

m∠FGH=32\°

measure\ arc\ AJ=112\°

substitute in the formula

32\°=\frac{1}{2} *[112\°-measure\ arc\ FH]

64\°=[112\°-measure\ arc\ FH]

measure\ arc\ FH=112\°-64\°=48\°

therefore

<u>the answer is</u>

the measure of the arc FH is 48\°

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