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Greeley [361]
2 years ago
14

The results of a poll show that the true proportion of students who prefer the new schedule is likely in the interval (0.195,0.2

45).
What is the point estimate of the proportion of students who prefer the new schedule
Mathematics
1 answer:
mojhsa [17]2 years ago
4 0

The point estimate of the proportion of students who prefer the new schedule is 0.22.

Definition of Point Estimate

Point estimation is a technique used in statistics to determine a single value that will serve as the "best guess" or "best estimate" of an unidentified population characteristic, known as the point estimate. More precisely, in order to produce a point estimate, we apply a point estimator to the data.

For the confidence interval (0.195, 0.245), point estimate is calculated as follows,

p = (0.195 + 0.245) / 2

p = 0.44 / 2

p = 0.22

Hence, the point estimate of the proportion of students who prefer the new schedule comes out to be 2.2.

Learn more about point estimate here:

brainly.com/question/17514579

#SPJ1

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Answer:

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Step-by-step explanation:

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2 years ago
Heather spend 2/7 of her money buying presents. she then had €48.65 left how much had she at first?​
Kisachek [45]

Given :

Heather spend 2/7 of her money buying presents.

She then had €48.65 left.

To Find :

The initial amount of money she had.

Solution :

Let, initial amount she had is €x.

So,

x - \dfrac{2x}{7} = 48.65\\\\\dfrac{5x}{7} = 48.65 \\\\x = \dfrac{48.65\times 7}{5}

x = €68.11

Therefore, initially he had €68.11 .

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3 years ago
There are 252525 students in Ms. Nguyen's second-grade class. In the class election, 444 students voted for Benjamin, 121212 vot
kozerog [31]

Answer:

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8 0
3 years ago
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7 0
3 years ago
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A quiz consists of six multiple choice questions. Each question has four choices. A student who forgot to study guesses randomly
jeka94

Answer:

0.9945 = 99.45% probability that the student answers at most four questions correctly

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the student answers correctly, or he/she does not. The probability of the student answering a question correctly is independent of any other question. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A quiz consists of six multiple choice questions.

This means that n = 6

Each question has four choices. Student guesses randomly.

This means that p = \frac{1}{4}

What is the probability that the student answers at most four questions correctly?

This is:

P(X \leq 4) = 1 - P(X > 4)

In which

P(X > 4) = P(X = 5) + P(X = 6). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{6,5}.(0.25)^{5}.(0.75)^{1} = 0.0053

P(X = 6) = C_{6,6}.(0.25)^{6}.(0.75)^{0} = 0.0002

P(X > 4) = P(X = 5) + P(X = 6) = 0.0053 + 0.0002 = 0.0055

P(X \leq 4) = 1 - P(X > 4) = 1 - 0.0055 = 0.9945

0.9945 = 99.45% probability that the student answers at most four questions correctly

6 0
3 years ago
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