3 years ago

Will mark as brainliest Thanks (only if you get the right answer)

Mathematics

1 answer:

Elis [28]3 years ago

7 0

It is 40 I just had that one and got it right

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Simplify. (–28xy) ÷ (4) –7xy 7xy -1/7xy 1/7xy

Colt1911 [192]

-28xy/4

-7xy

Therefore, the first answer is correct.

Hope this helps!

6 0

3 years ago

4. In Ghana the high temperatures in degrees Fahrenheit for five days in January were -14°

S_A_V [24]

Answer:

Step-by-step explanation:

5 0

3 years ago

Se arrastra un bloque de 18 kg a través de una superficie con una fuerza de 300 N en donde el coeficiente de fricción de dicha s

ozzi

Answer:

$10.9\ \text{m/s}^2$

Step-by-step explanation:

m = Masa del bloque = 18 kg

F = Fuerza en el bloque = 300 N

$\mu$ = Coeficiente de fricción = 0.6

El equilibrio de fuerzas del sistema viene dado por

$F-f=ma\\\Rightarrow 300-0.6\times 18\times 9.81=18a\\\Rightarrow a=\dfrac{300-0.6\times 18\times 9.81}{18}\\\Rightarrow a=10.9\ \text{m/s}^2$

La aceleración del bloque es $10.9\ \text{m/s}^2$ .

8 0

3 years ago

Does anyone know 20=b/3 is in a one step equation

inna [77]

Answer:

b=60

Step-by-step explanation:

All you have to do in this equation is multiply both sides by 20 as we want to have the variable b on one side by itself. Doing this we get 60=b.

4 0

3 years ago

Read 2 more answers

I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find

netineya [11]

Answer:

see below

Step-by-step explanation:

mROP= 125°

mSOQ= mROP= 125°

mROQ=mPOS= 180°-125°= 55°

Sum of measures of all arcs in the circle= 2π

mRP= mQS=2π*125/360=25/36π

mQR=mPS=2π*55/360=11/36π

mPRQ= half circle= 2π/2= π

mRPQ= 2π-mQR= 2π- 11/36π= 61/36π

6 0

3 years ago