Answer:
(1) the surface area of the solute,
(2) the temperature of the solvent,
(3) the amount of agitation that occurs when the solute and the solvent are mixed.
Explanation:
The empirical formula of the compound is C. NiF₂.
<em>Step 1</em>. Calculate the <em>moles of each element</em>
The empirical formula is the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles.
So, our job is to calculate the molar ratio of Ni to F.
Moles of Ni = 9.11 g Ni × (1 mol Ni /(58.69 g Ni) = 0.1552 mol Ni
Moles of F = 5.89 g F × (1 mol F/19.00 g F) = 0.3100 mol F
<em>Step 2</em>. Calculate the <em>molar ratio</em> of the elements
Divide each number by the smallest number of moles
Ni:F = 0.1552:0.3100 = 1:1.997 ≈ 1:2
<em>Step 3</em>: Write the <em>empirical formula</em>
EF = NiF₂
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Answer: 2.75×10^-7m
Explanation:
The work function refers to the smallest energy a photon must posses in order to cause the ejection of electrons from a metal surface.
If Eo= hfo
Eo=work function of the metal
fo=threshold frequency
h= Plank's constant
But Eo= hf= hc/wavelength
Wavelength= hc/Eo
We convert Eo to joules
4.50×1.6×10^-19=7.2×10^-19J
c=3×10^8ms-1
h=6.6×10^-34Js
Wavelength= 3×10^8×6.6×10^-34/7.2×10^-19
2.75×10^-7m