Answer:
a) Keq = 4.5x10^-6
b) [oxaloacetate] = 9x10^-9 M
c) 23 oxaloacetate molecules
Explanation:
a) In the standard state we have to:
ΔGo = -R*T*ln(Keq) (eq.1)
ΔGo = 30.5 kJ/moles = 30500 J/moles
R = 8.314 J*K^-1*moles^-1
Clearing Keq:
Keq = e^(ΔGo/-R*T) = e^(30500/(-8.314*298)) = 4.5x10^-6
b) Keq = ([oxaloacetate]*[NADH])/([L-malate]*[NAD+])
4.5x10^-6 = ([oxaloacetate]/(0.20*10)
Clearing [oxaloacetate]:
[oxaloacetate] = 9x10^-9 M
c) the radius of the mitochondria is equal to:
r = 10^-5 dm
The volume of the mitochondria is:
V = (4/3)*pi*r^3 = (4/3)*pi*(10^-15)^3 = 4.18x10^-42 L
1 L of mitochondria contains 9x10^-9 M of oxaloacetate
Thus, 4.18x10^-42 L of mitochondria contains:
molecules of oxaloacetate = 4.18x10^-42 * 9x10^-9 * 6.023x10^23 = 2.27x10^-26 = 23 oxaloacetate molecules
<u>Answer:</u> The frequency of the radiation is 33.9 THz
<u>Explanation:</u>
We are given:
Wave number of the radiation, 
Wave number is defined as the number of wavelengths per unit length.
Mathematically,

where,
= wave number = 
= wavelength of the radiation = ?
Putting values in above equation, we get:

Converting this into meters, we use the conversion factor:
1 m = 100 cm
So, 
- The relation between frequency and wavelength is given as:

where,
c = the speed of light = 
= frequency of the radiation = ?
Putting values in above equation, we get:


Converting this into tera Hertz, we use the conversion factor:

So, 
Hence, the frequency of the radiation is 33.9 THz
There are 1.923×10^23 formula units in 30.4g mgcl2
molar mass of mgcl2= 95.211g/mol
magnesium= 24.305g/mol
chlorine= 35.45g/mol times 2
24.305+(35.45*2)= 95.211g/mol
sample divided by molar mass times Avogadro's number gives u the formula units
30.4÷ 95.211= .31929
.3193*6.022=1.9288
Answer:
Go on the site named " the chemistry of ice cream ''
Explanation:
https://davidson.weizmann.ac.il/en/online/sciencepanorama/chemistry-ice-cream