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Answer:
Cost of one roll of plain wrapping:
Cost of one roll of holiday wrapping paper:
Step-by-step explanation:
Let be "p" the cost in dollars of one roll of plain wrapping paper and "h" the cost in dollars of one roll of holiday wrapping paper.
Based on the information given, we can set up this system of equations:
In order to solve it, we can use the Substitution method. The steps are:
1. Solve for "p" from the first equation:
2. Substitute the above into the second equation and solve for "h":
3. Substitute the value of "h" into :
Answer:
x = 2 , y = 0 , z = 3
Step-by-step explanation:
Cramer's rule is a rule through which we can find the solution of linear equation.
we have the three linear equations as
x+2y+3z=11
2x+y+2z=10
3x+2y+z=9
AX=B
A: coefficient matrix
X= unknown vectors(x,y,z)
D = values of the linear equation (11 , 10 , 9)
now we find the determinant of the given linear equation
determinant of the matrix will be
A = = 1(1-4) - 2(2-6) + 3(4 - 3)
= 1(-3) - 2(-4) + 3(1)
= -3+8+3 = 8
also D
so the determinant is Non zero we can apply Cramer's rule
we will be replacing the first column of the coefficient matrix A with the values of D
by replacing the first column we will get the value of the variable 'x'
Dx = = 11(1-4) -2(10-18) + 3(20-9) = -33+16+33 = 16
x = =
= 2
similarly
Dy = = 1(10-18) -11(2-6) + 3(18 -30) = -8 +44 -36 = 0
y = = 0
Dz= = 1(9 - 20) -2(18 - 30) + 11(4 -3) = -11 +24 +11 = 24
z = =
so we have the solution as
x = 2 , y = 0 , z = 3
Therefore the solution for the given linear equations is (2,0,3).