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chubhunter [2.5K]
3 years ago
12

How many positive integers $n$ satisfy $ floor sqrt n floor = 5$?

Mathematics
1 answer:
Temka [501]3 years ago
5 0

That's all the square roots of the form 5.xxxx. The numbers start at 5² and end at 6²-1.

So that's 6² - 5² = 11 numbers. We can list them:

25,26,27,28,29,30,31,32,33,34,35

Answer: 11


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Solve using elimination.<br> 5x + 7y = -6<br> 4x + 7y = -9
Ede4ka [16]
Answer:

Simplifying
5x + 7y = -6

Solving
5x + 7y = -6

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7y' to each side of the equation.
5x + 7y + -7y = -6 + -7y

Combine like terms: 7y + -7y = 0
5x + 0 = -6 + -7y
5x = -6 + -7y

Divide each side by '5'.
x = -1.2 + -1.4y

Simplifying
x = -1.2 + -1.4y
__________________________________

Simplifying
4x + 7y = -9

Solving
4x + 7y = -9

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7y' to each side of the equation.
4x + 7y + -7y = -9 + -7y

Combine like terms: 7y + -7y = 0
4x + 0 = -9 + -7y
4x = -9 + -7y

Divide each side by '4'.
x = -2.25 + -1.75y

Simplifying
x = -2.25 + -1.75y
6 0
3 years ago
MATH HELP PLZZZZZ!!! 10pts
kykrilka [37]
First i got the area which is : A= a+b divided by 2 x height 
=2.5+3.5 divided by 2 x 2= 6
Area = 6

To get the perimeter you just add all the sides together so: 3.5+2.5+2.5+2.5= 11
8 0
3 years ago
Read 2 more answers
PLSSSSS HELPP MEEEEEEEEE PLS RESPOND TO ME
aivan3 [116]

Answer:

HOLAAAAAO

Step-by-step explanation:

8 0
3 years ago
Please answer asap!!!!!
kherson [118]

Step-by-step explanation:

The equation of a circle can be the expanded form of

\large \text{$(x-a)^2+(y-b)^2=r^2$}(x−a)

2

+(y−b)

2

=r

2

where rr is the radius of the circle, (a,\ b)(a, b) is the center of the circle, and (x,\ y)(x, y) is a point on the circle.

Here, the equation of the circle is,

\begin{gathered}\begin{aligned}&x^2+y^2+10x-4y-20&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4-49&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &x^2+10x+25+y^2-4y+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &(x+5)^2+(y-2)^2&=&\ \ 7^2\end{aligned}\end{gathered}

⟹

⟹

⟹

⟹

x

2

+y

2

+10x−4y−20

x

2

+y

2

+10x−4y+25+4−49

x

2

+y

2

+10x−4y+25+4

x

2

+10x+25+y

2

−4y+4

(x+5)

2

+(y−2)

2

=

=

=

=

=

0

0

49

49

7

2

From this, we get two things:

\begin{gathered}\begin{aligned}1.&\ \ \textsf{Center of the circle is $(-5,\ 2)$.}\\ \\ 2.&\ \ \textsf{Radius of the circle is $\bold{7}$ units. }\end{aligned}\end{gathered}

1.

2.

Center of the circle is (−5, 2).

Radius of the circle is 7 units.

Hence the radius is 7 units.

4 0
2 years ago
How many solutions 9x +2y =9 -3x + y=2
Tju [1.3M]

Answer:

4

Step-by-step explanatio

6 0
3 years ago
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