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chubhunter [2.5K]
3 years ago
12

How many positive integers $n$ satisfy $ floor sqrt n floor = 5$?

Mathematics
1 answer:
Temka [501]3 years ago
5 0

That's all the square roots of the form 5.xxxx. The numbers start at 5² and end at 6²-1.

So that's 6² - 5² = 11 numbers. We can list them:

25,26,27,28,29,30,31,32,33,34,35

Answer: 11


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