Answer:
b) y=2x-3 y-int.=-3 x= 1/2 (think of rise over run)= up 2 over 1. C) IDK D) y=2/4+3 E)7/2-8
Step-by-step explanation:
<h2>when you solve in slope intercept form ex. 3x+4y=12 move 3x by subtracting to the other side. 3x-3x=0 cancel then your left with 4y=-3 (you moved to both sides)+ 12 divide the equation by 4. left with 4divided by 4 cancels left with y= -3+12 divided by 4= y=3/4+8</h2><h2 /><h2>Remember if positive subtract if negative number add to both sides.</h2>
X³-8=x-2: Original equation.
x³-x-6=0: Subtract x and add 2 to both sides.
(x-2)(x²+2x+3): Factor the equation
x-2=0; x²+2x+3=0: Separate the expressions into equations
x=2: Add 2 to both sides
x²+2x+3=0: Quadratic Formula
x= 2, <u>-2+√-8</u>,<u>-2-√-8</u>
<u /> 2 2
Answer:
y > 7
Step-by-step explanation:
Answer:

Explanation:
You need to find the probability that exactly three of the first 11 inspected packages are damaged and the fourth is damaged too.
<u>1. Start with the first 11 inspected packages:</u>
a) The number of combinations in which 11 packages can be taken from the 20 available packages is given by the combinatory formula:


b) The number of combinations in which 3 damaged packages can be chossen from 7 damaged packages is:

c) The number of cominations in which 8 good packages can be choosen from 13 good pacakes is:

d) The number of cominations in which 3 damaged packages and 8 good packages are chosen in the first 11 selections is:

e) The probability is the number of favorable outcomes divided by the number of possible outcomes, then that is:

Subsituting:


<u>2. The 12th package</u>
The probability 12th package is damaged too is 7 - 3 = 4, out of 20 - 11 = 9:
<u>3. Finally</u>
The probability that exactly 12 packages are inspected to find exactly 4 damaged packages is the product of the two calculated probabilities:

Solution
Asymptote:
Vertical Asymptote
- The vertical asymptotes of a rational function are determined by the denominator expression.
- The expression given is:

- The denominator of (x- 36) determines the asymptote line.
- The vertical asymptote defines where the rational function isundefined. Iin order for a rational function to be undefined, its denominator must be zero.
- Thus, we can say:

- Thus, the vertical asymptote is

Horizontal Asymptote:
- The horizontal asymptote exists in two cases:
1. When the highest degree of the numerator is less han the degree of the demnominator. In this case, the horizontal asymptote is y = 0
2. When the highest degee sof the numerator and tdenominator are the same. In this case, the horizontal asymptote is

- For our question, we can see that the highest degrees of the numerator and denominator are the same. Thus, we have the Horizontal Asymptote to be:

End behavior:
- The end behavior is examining the y-values of the function as x tendsto negative and positive infinity.
- Thus, we have that:

Final Answers
Asymptotes:

End behavior: