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3 years ago

Please help must show work

Mathematics

1 answer:

hjlf3 years ago

3 0

Answer:

b) y=2x-3 y-int.=-3 x= 1/2 (think of rise over run)= up 2 over 1. C) IDK D) y=2/4+3 E)7/2-8

Step-by-step explanation:

<h2>when you solve in slope intercept form ex. 3x+4y=12 move 3x by subtracting to the other side. 3x-3x=0 cancel then your left with 4y=-3 (you moved to both sides)+ 12 divide the equation by 4. left with 4divided by 4 cancels left with y= -3+12 divided by 4= y=3/4+8</h2><h2 /><h2>Remember if positive subtract if negative number add to both sides.</h2>

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There are 10 rolls of film in a box and 3 are defective. two rolls are selected without replacement. what is the probability of

german

P(picking one defective) = 3/10
P(picking a 2nd defective) = 2/9

P(1 and 2 defective) = 3/10 x 2/9 = 6/90 = 0.066

Second method using combination:
³C₂ / ¹⁰C₂ = 1/15 = 0.066

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4 years ago

Suppose two fair six-sided dice are rolled. what is the probability that they will both come up with the same number?

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You have a 16.7% chance of rolling doubles

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3 years ago

Solve the inequality 4i−4(i+2)≥6(8i−8) and write the solution in interval notation

devlian [24]

Answer:

$(-\infty,\frac{25}{24}]$

Step-by-step explanation:

Assuming $i$ is a variable:

$4i-4(i+2)\geq6(8i-8)\\\\4i-4i+2\geq48i-48\\\\2\geq48i-48\\\\50\geq48i\\\\\frac{50}{48}\geq i\\ \\\frac{25}{24}\geq i\\ \\i\leq\frac{25}{24}\\ \\(-\infty,\frac{25}{24}]$

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2 years ago

A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed

Natali [406]

Answer:

$t=\frac{1.17-1.04}{\sqrt{\frac{0.11^2}{8}+\frac{0.09^2}{8}}}}=2.587$

$df=n_{1}+n_{2}-2=8+8-2=14$

Since is a one sided test the p value would be:

$p_v =P(t_{(14)}>2.587)=0.0108$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, we have enough evidence to reject the null hypothesis on this case and the 25 mil film have a mean greater than the 20 mil film so then the claim is not appropiate

Step-by-step explanation:

Data given and notation

$\bar X_{1}=1.17$ represent the mean for the sample 1 (25 mil film)

$\bar X_{2}=1.04$ represent the mean for the sample 2 (20 mil film)

$s_{1}=0.11$ represent the sample standard deviation for the sample 1

$s_{2}=0.09$ represent the sample standard deviation for the sample 2

$n_{1}=8$ sample size selected for 1

$n_{2}=8$ sample size selected for 2

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if reducing the film thickness increases the mean speed of the film, the system of hypothesis would be:

Null hypothesis: $\mu_{1} \leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{1.17-1.04}{\sqrt{\frac{0.11^2}{8}+\frac{0.09^2}{8}}}}=2.587$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=8+8-2=14$

Since is a one sided test the p value would be:

$p_v =P(t_{(14)}>2.587)=0.0108$

4 0

3 years ago

If I have to drive 1,044 miles and my car is 18mpg and the current cost of gas is 1.45 a gallon, what is my total cost of gas to

aksik [14]

Answer: I think you would spend $84.10 but I can’t be sure because I don’t know how many gallons of gas your tank holds

Step-by-step explanation:

4 0

3 years ago

Please help must show work ​

Please help must show work