<u><em>I don't know if this is 100% correct...but i think this is how you would solve this problem!!!</em></u><u><em /></u><em />
OOOKKKKK.........
We all know that a well is circular. So, First, lets find out the circumference of the wheel.
Given :
radius = 10 feet
π = 22 / 7
We know,
Circumference = 2πr
= 2 × (22 / 7) × 10
= 62.9 ft.
Now,
One revolution means the wheel has covered a distance equal to its circumference. So, 22 revolutions per minute means that the wheel is covering 22 times its circumference in 1 minute. So, Lets convert the revolution to feet.
Given,
The wheel is travelling at 22 revolutions per minute.
= 22 * Circumference per minute
= 22 * 62.9 ft. per minute
= 1383.8 ft. per minute
Now, that we know how much feet it is travelling in 1 minute, we can easily find how much it takes it to travel 10 feet.
Using unitary method,
The wheel travels 1383.8 ft. in 1 minute
The wheel travels 1383.8 ft. in 60 seconds.
The wheel travels 1 ft. in (60 / 1383.8) seconds.
The wheel travels 10 ft. in (60 / 1383.8) * 10 seconds.
= 0.4 seconds
So, the answer is 0.4 seconds. Of course...the answer is rounded!!
<h3>
Answer: quadrant 3</h3>
Work Shown:
Divide 1300 over 360
1300/360 = 3.611 approximately
Focus on the whole part 3. There are 3 full revolutions
3*360 = 1080, which subtracts off to get 1300-1080 = 220 left over.
The remainder 220 tells us where the angle points. It's in quadrant 3 since 220 degrees is between 180 degrees and 270 degrees.
Answer:
72 mph
Step-by-step explanation:
<em>Please give brainliest</em>
You have distance =210 miles
Increase it by 20%
210+(210*0.2) = 252 miles I wrote 0.2 instead of writing 20%/100% hope you understand.
The new route is 252 miles
Time travelled = 3.5 hours
Speed=distance/time
Speed = 252/3.5 = 72 mph
Answer:
c. 108.4
Step-by-step explanation:
cos theta = (u dot v)/ (||u|| ||v||)
where dot stands for dot product and || || is the magnitude
u = (1,5) v= (7,-4)
u dot v = (1*7 + 5*-4) = 7-20 = -13
||u|| = sqrt( 1^2 +5^2) = sqrt(1+25) = sqrt(26)
||v|| = sqrt(7^2 + (-4)^2) = sqrt(49+16) = sqrt(65)
cos theta = -13/ sqrt(26) sqrt(65)
cos theta = -13 /sqrt(1690)
theta = arccos (-13/sqrt(1690))
theta = 108.43
This is a horizontal line at y = -3. If you want to find it mathematically, you could find the slope (y2-y1)/(x2-x1) and you would get 0 over 5, so you know the slope is zero. Pick either point and substitute the numbers into point-slope formula. I went with (3, -3) and got (y - -3) = 0(x-3). The right side is just 0, and if you subtract three from both sides to isolate y, you get the equation y = -3.