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3 years ago

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Heather has a bag with 8 marbles, 8 tennis balls, 4 apples, and 5 books. What is the ratio of books to tennis balls? 4:7, 8:8, 8

:5, 5:8

1 answer:

mafiozo [28]3 years ago

3 0

Answer:

The ratio is 5:8.

Step-by-step explanation:

Since we are looking for books and tennis balls, we have to look at how many there are. There are 5 books and 8 tennis balls. We're looking for the ratio of books to tennis balls, so it has to be in that order. 5:8

I hope this helped! :-)

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Felicia is solving the expression -5(3x+2)+10x. Gregory is solving the expression -12-4x+?+?x. Both students simplified their an

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Answer:

see the explanation

Step-by-step explanation:

we have

<em>Felicia</em>

$-5(3x+2)+10x$

Apply distributive property

$-5(3x)-5(2)+10x$

$-15x-10+10x$

Combine like terms

$-5x-10$

Let

a ----> the missing term with coefficient x in Gregory's expression

b ----> the missing constant term in Gregory's expression

so

$-12-4x+ax+b$

equate Gregory's expression to Felicia's expression

$-12-4x+ax+b=-5x-10$

so

$-12+b=-10$ -----> $b=2$

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Gregory's expression is

$-12-4x+2-x$

therefore

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2. Which expression is equivalent to 5(n + 3) - 10? A. 5+1 +5+3 – 10 B. 5 • n + 5 + 3 - 10 C. 5. n + 5 • 3 – 10 D. 5 • n • 5 • 3

GuDViN [60]

Answer:

5n+5

Step-by-step explanation:

5(n+3)-10

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Several years ago, 50% of parents who had children in grades K-12 were satisfied with the quality of education the students r

galina1969 [7]

Answer:

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Step-by-step explanation:

We have to see if 50% = 0.5 is part of the confidence interval.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

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For this problem, we have that:

$n = 1095, \pi = \frac{478}{1095} = 0.4365$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

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The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 + 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4612$

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Answer:

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Step-by-step explanation:

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