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Kobotan [32]
3 years ago
13

Un bloque con una masa de 2.6 kg está unida a un resorte horizontal con constante elástica k = 6.7x102 N/m. Si el bloque se jala

hasta 41.2 cm y se suelta, ¿cuál es la variación de energía potencial elástica? Despreciar la fricción entre la superficie y el bloque
Physics
1 answer:
Rudiy273 years ago
7 0

Answer:

U = 56.86 [J]

Explanation:

Para solucionar este tipo de problemas debemos calcular la energía potencial elástica debido al estiramiento del resorte.

U = 0.5*k*(x)^2

U_{elas}=0.5*k*(x)^{2} \\U_{elas}=0.5*(6.7*10^2)*(0.412)^{2}\\ U_{elas}=56.86[J]

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