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Leni [432]
3 years ago
5

A 0.45 kg football traveling at a speed of 22 m/s is caught by a stationary receiver. If the football comes to a rest in the rec

eiver's arms, the magnitude of the impulse imparted to the receiver by the ball is
Physics
1 answer:
joja [24]3 years ago
4 0

Answer:

0.9Ns

Explanation:

Impulse formula is expressed as;

Impulse = Ft = m(v-u)

Impulse = m(v-u)

m is the mass of football = 0.45kg

v is the final velocity = 22m/s

u is the initial velocity = 0m/s

Impulse = 0.45(22-0)

Impulse = 0.45 * 22

Impulse =  0.9Ns

Hence the magnitude of the impulse imparted to the receiver by the ball is 0.9Ns

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DerKrebs [107]

The answer is:

A. They can be formed into wires.

B.They are shiny.

D. They are good conductors

E.can be easily shaped by hammering or pounding.

The explanation:

Let's see the characteristics of the most metals:

1) the most metals can be hit by a hammer and form a thin sheets without breaking and this called malleability.

for example: Aluminium and copper

2) They can form into a very thin wires and this called ductility

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3) The metal can conduct the heat and the electricity very easy and quick, this mean that the meals are good conductor for the heat and electricity.

4)The metals like gold can be used at jewellery because it is very shiny.

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The strong nuclear force holds the nucleus of an atom together.  

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The gravitational force between two asteroids is 2.59 × 10 (exponent)-6 N. The centers of mass are 2000 meters away and their ma
makkiz [27]

Answer:

2.79 \times 10^5 \ \text{kg}

Explanation:

Newton's Law of Universal Gravitation:

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  • m_1 = mass of Object 1 (kg)
  • m_2 = mass of Object 2 (kg)
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Let's convert our given information to scientific notation:

  • 2000 \ m \rightarrow 2.0 \times 10^3 \ m

Now using the gravitational force and the distance between centers of mass that are given, we can plug these into Newton's law:

  • 2.59 \times 10^-^6 $\ N = 6.67 \times 10^-^1^1 \ N \frac{m^2}{kg^2}  \times \frac{m_1 m_2}{(2.0 \times 10^3 \ m)^2}

Remove the units for better readability.

  • 2.59 \times 10^-^6=6.67 \times 10^-^1^1 \frac{m_1m_2}{(2.0 \times 10^3)^2}

Divide both sides of the equation by the gravitational constant G.

  • \frac{2.59 \times 10^-^6}{6.67 \times 10^-^1^1} =\frac{m_1m_2}{(2.0 \times 10^3)^2}

Distribute the power of 2 inside the parentheses.

  • \frac{2.59 \times 10^-^6}{6.67 \times 10^-^1^1} =\frac{m_1m_2}{2.0 \times 10^6}

If we evaluate the left side of the equation, we get:

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Multiply both sides of the equation by r.

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In order to find the mass of one asteroid, we can use the fact that both asteroids have the same mass, therefore, we can rewrite m_1m_2 as m^2.

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Square root both sides of the equation.

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Since m is in units of kg, we can state that the mass of each asteroid is 2.79 * 10⁵ kg.

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