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Leni [432]
2 years ago
5

A 0.45 kg football traveling at a speed of 22 m/s is caught by a stationary receiver. If the football comes to a rest in the rec

eiver's arms, the magnitude of the impulse imparted to the receiver by the ball is
Physics
1 answer:
joja [24]2 years ago
4 0

Answer:

0.9Ns

Explanation:

Impulse formula is expressed as;

Impulse = Ft = m(v-u)

Impulse = m(v-u)

m is the mass of football = 0.45kg

v is the final velocity = 22m/s

u is the initial velocity = 0m/s

Impulse = 0.45(22-0)

Impulse = 0.45 * 22

Impulse =  0.9Ns

Hence the magnitude of the impulse imparted to the receiver by the ball is 0.9Ns

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Explanation:

Your box weighs 400g, or 0.4kg. In order to lift it, you need to overcome the force of gravity. F = ma, and acceleration due to gravity is -9.8 m/s^2. So gravity acts on the box with a force of 0.4 kg * -9.8 m/s^2 = -3.92 N. A force of +3.92 N is required to overcome this.

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Convert the volume 8.06 in.3 to m3, recalling that1in. =2.54cmand100cm=1m. Answer in units of m3.
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Answer: 8.06 in³=1.321 x 10⁻⁴ m³
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