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SpyIntel [72]
3 years ago
12

Ethan builds two different kinds of chairs, rockers and swivels. It takes him 3 hours to build a rocker and requires 2 oz of sta

in. It takes him 2 hours to build a swivel chair and requires 8 oz of stain. Ethan has 56 oz of stain available and he can only work up to 24 hours. He makes $12 profit on each rocker and $10 profit on each swivel chair. 1. Since there cannot be negative chairs, create two constraints to represent this. 2.Create a constraint for the hours it takes to build the chairs. 3. Create a constraint for the stain it takes for the chairs. PLEASE HELP
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

Answer:

(1) x\geq 0\; \text {and}\;y\geq 0

(2) 3x + 2y\leq 24

(3) x+4y\leq 28

Step-by-step explanation:

Let x and y be the numbers of rockers and swivels made by Ethan.

(1) Since the number of chairs can't be negative. So,

x\geq0 and y\geq 0 are the two constraints.

(2) He can work a maximum of 24 hours.

The time required to make 1 rocker chair and 1 swivels chair are 3 hr and 2 hr respectively.

So, the time required to make x rocker chair = 3x hr

and the time required to make y swivel chair = 2y hr.

The total time required is  3x + 2y hr which can't be more than the available time, 24 hr.

So, the required constraint is

3x + 2y\leq 24

(3) Similarly,

As 1 rocker chair requires 2 oz strain and 1 swivel chair required 8 ox strain.

So, to make x rocker chair 2x oz required and make y swivel chair 8y oz required which can't be more than the available oz, 56.

So, the required constraint is

2x + 8y\leq 56

\Rightarrow x+4y\leq 28.

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3 0
2 years ago
If y is the circumcenter is angle STU find each measure
snow_tiger [21]

Answer:

Measures are SV=9 units., SY=14 units, YW=\sqrt75units , YW=\sqrt27units

Step-by-step explanation:

Given Y is the circumcenter of ΔSTU. we have to find the measures SV, SY, YW and YX.

As Circumcenter is equidistant from the vertices of triangle and also The circumcenter is the point at which the three perpendicular bisectors of the sides of the triangle meet.

Hence, VY, YW and YX are the perpendicular bisectors on the sides ST, TU and SU.

Given ST=18 units.

As VY is perpendicular bisector implies SV=9 units.

Also in triangle VTY

YT^{2}=VY^{2}+VT^{2}

⇒ 14^{2}=VY^{2}+9^{2}

⇒ VY^{2}=115

As vertices of triangle are equidistant from the circumcenter

⇒ SY=YT=UY=14 units

Hence, SY is 14 units

In ΔUWY, UY^{2}=YW^{2}+UW^{2}

⇒ 14^{2}=YW^2+11^{2}

⇒ YW^2=196-121=75 ⇒ YW=\sqrt75units

In ΔYXU, UY^{2}=YX^{2}+XU^{2}

⇒ 14^{2}=YX^2+13^{2}

⇒ YX^2=196-169=27 ⇒ YW=\sqrt27units

Hence, measures are SV=9 units., SY=14 units, YW=\sqrt75units , YW=\sqrt27units





4 0
2 years ago
The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo
oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY =  \sqrt{x^2+y^2}

Therefore, the length between points AB is

length AB = \sqrt{(-4 - (-2))^2+(-1-3)^2}

= \sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2}  = \sqrt{20}  = 4.472 units

Similarly, length BC is given by

Length BC =  \sqrt{(-4)^2+1^2} =  \sqrt{17} = 4.123 units

Length CD = \sqrt{(-2)^2+5^2} =  \sqrt{29} = 5.385 units

Length DA = \sqrt{(8)^2+(-2)^2} =  \sqrt{68} = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

 S_{\bigtriangleup} = (\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|

= (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

S_{{\bigtriangleup}ABC} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|

= =(\frac{1}{2})|-4-6 -8|= 9 units^2

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

S_{{\bigtriangleup}ACD'} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2} = 10.5 units²

Area of polygon =   S_{{\bigtriangleup}ABCD'} = S_{{\bigtriangleup}ABC} + S_{{\bigtriangleup}ACD'} = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0
2 years ago
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Answer:

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2 years ago
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