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garik1379 [7]
3 years ago
8

What's 12 divided by 15 ? will mark BRAINLIEST! i love wap!​

Mathematics
2 answers:
mafiozo [28]3 years ago
8 0

Answer:

0.8

Step-by-step explanation:

Brut [27]3 years ago
4 0

Step-by-step explanation:

0.8 is answer

see my calculator

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Help me asap!!!! please
Lubov Fominskaja [6]

Answer:

x = 3 should be the answer

Step-by-step explanation:

y is not graphed so y isn't part of the equation while x is so its X = K (K being the number that it goes up on) same thing applies to y if its horizontal then the equation is Y = K)

6 0
2 years ago
Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true
IgorLugansk [536]

Answer:

(a) 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

Step-by-step explanation:

We are given that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.75.

(a) Also, the average porosity for 20 specimens from the seam was 4.85.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                      P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average porosity = 4.85

            \sigma = population standard deviation = 0.75

            n = sample of specimens = 20

            \mu = true average porosity

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u>So, 95% confidence interval for the true mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                     of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                            = [ 4.85-1.96 \times {\frac{0.75}{\sqrt{20} } } , 4.85+1.96 \times {\frac{0.75}{\sqrt{20} } } ]

                                            = [4.52 , 5.18]

Therefore, 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) Now, there is another seam based on 16 specimens with a sample average porosity of 4.56.

The pivotal quantity for 98% confidence interval for the population mean is given by;

                      P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average porosity = 4.56

            \sigma = population standard deviation = 0.75

            n = sample of specimens = 16

            \mu = true average porosity

<em>Here for constructing 98% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u>So, 98% confidence interval for the true mean, </u>\mu<u> is ;</u>

P(-2.3263 < N(0,1) < 2.3263) = 0.98  {As the critical value of z at 1% level

                                                   of significance are -2.3263 & 2.3263}  

P(-2.3263 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} <  2.3263 ) = 0.98

P( \bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } } ]

                                            = [ 4.56-2.3263 \times {\frac{0.75}{\sqrt{16} } } , 4.56+2.3263 \times {\frac{0.75}{\sqrt{16} } } ]

                                            = [4.12 , 4.99]

Therefore, 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

7 0
3 years ago
What is the value of g(2)? Please show work
4vir4ik [10]

By the inequality for x over on the right side if x is equal to or greater than 2 you use the bottom equation.

G(2) means x is 2.

Using the bottom equation replace the x’s with 2 and solve.

X^3 -9x^2 +27x-25

2^3 -9(2)^2+27(2)-25

Simplify:

8 -36 + 54-25 =1

The answer is A. 1

8 0
3 years ago
Can someone help me? Brainliest + Points!
iris [78.8K]

Answer:

D. \frac{2}{5}

Step-by-step explanation:

Since we know that the odds of an events can be found by dividing the probability that an event will occur by the probability that the event will not occur.

\text{Odds of an event}=\frac{\text{Probability that event will occur}}{\text{Probability that event will not occur}}

Probability of an event not occurring can be found by subtracting probability of the event occurring from 1.

\text{Odds of an event}=\frac{\text{Probability that event will occur}}{1-\text{Probability that event will occur} }  

We have been given that probability of an event is 2/7.  

Upon substituting our given values in above formula we will get,

\text{Odds of the given event}=\frac{\frac{2}{7}}{1-\frac{2}{7}} }

\text{Odds of the given event}=\frac{\frac{2}{7}}{\frac{7-2}{7}} }

\text{Odds of the given event}=\frac{\frac{2}{7}}{\frac{5}{7}} }

\text{Odds of the given event}=\frac{2}{7}\times \frac{7}{5}

\text{Odds of the given event}=\frac{2}{5}

Therefore, the odds of the same event are \frac{2}{5} and option D is the correct choice.



7 0
3 years ago
What temperature is 23 degrees above freezing in fahrenheit
jek_recluse [69]
The temperature that is 23 degrees above freezing is 55 because the freezing level is 32 and you add 23 to that
7 0
3 years ago
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