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Vlad1618 [11]
4 years ago
14

Write the number seven and one - third as a decimal rounded to the nearest hundredth

Mathematics
2 answers:
Levart [38]4 years ago
7 0

Answer:

7\frac{1}{3}=7.33

Step-by-step explanation:

To find : Write the number seven and one - third as a decimal rounded to the nearest hundredth ?

Solution :

Write the number seven and one - third in numeric form is

n=7\frac{1}{3}

Writing number from mixed fraction to simpler fraction,

n=\frac{22}{3}

To write in decimal form,

We divide 22 by 3,

n=7.333...

Round nearest to hundredth,

n=7.33

Therefore, 7\frac{1}{3}=7.33

bagirrra123 [75]4 years ago
4 0
Well you know you keep the 7. 1/3 well you see it as .3333 so just go 7.33 because 7.333 and since it's a 3 you keep it.
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The spending limit on John’s credit card is given by the function f(x)=15,000+1.5x , where x is his monthly income. f^-1x . The
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<span>1.
"The spending limit on John’s credit card is given by the function f(x)=15,000+1.5x"

means that if the monthly income of John is $ 5,000 ,he can spend at most 

f(5,000)=15,000+1.5*5,000=15,000+ 7,500=22, 500 (dollars)

Or for example

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2.
Now, assume that the maximum amount that John can spend is y.

Then, y=15,000+1.5x

we can express x, the monthly income, in terms of y by isolating x:

</span>y=15,000+1.5x
<span>
1.5x = y-15,000


</span>x= \frac{y-15,000}{1.5}
<span>
thus, in functional notation, x, the monthly income, is a function , say g, of variable y, the max amount:

</span>x=g(y)=\frac{y-15,000}{1.5}

since we generally use the letter x for the variable of a function, we write g again as:

g(x)=\frac{x-15,000}{1.5}
<span>
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tells us that if the maximum amount that John can spend is 50,000 $, then his monthly income is 23,333 $.

3.

If John's limit is $60,000, his monthly income is 

</span>g(60,000)=\frac{60,000-15,000}{1.5}= \frac{45,000}{1.5}=30,000<span>
 dollars.


Answer: $ 30,000

Remark: g is called the inverse function of f, since it undoes what f does.

instead of g(x), we could use the notation </span>f ^{-1}(x)<span>



</span>
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