Write the number seven and one - third as a decimal rounded to the nearest hundredth
2 answers:
Answer:
Step-by-step explanation:
To find : Write the number seven and one - third as a decimal rounded to the nearest hundredth ?
Solution :
Write the number seven and one - third in numeric form is
Writing number from mixed fraction to simpler fraction,
To write in decimal form,
We divide 22 by 3,
Round nearest to hundredth,
Therefore,
You might be interested in
Answer:
Option D is correct
Step-by-step explanation:
From the question, we have:
Required
The tree diagram
The selection process is as follows:
-- i.e. we write sack 2 as a subset of 1
-- i.e. we write sack 3 as a subset of 2
<em>The only tree diagram that illustrates this is: option D</em>
Answer:
Proofs are in the explantion.
Step-by-step explanation:
We are given the following:
1) for integer
.
1) for integer
.
a)
Proof:
We want to show .
So we have the two equations:
a-b=kn and c-d=mn and we want to show for some integer r that we have
(a+c)-(b+d)=rn. If we do that we would have shown that .
kn+mn = (a-b)+(c-d)
(k+m)n = a-b+ c-d
(k+m)n = (a+c)+(-b-d)
(k+m)n = (a+c)-(b+d)
k+m is is just an integer
So we found integer r such that (a+c)-(b+d)=rn.
Therefore, .
//
b) Proof:
We want to show .
So we have the two equations:
a-b=kn and c-d=mn and we want to show for some integer r that we have
(ac)-(bd)=tn. If we do that we would have shown that .
If a-b=kn, then a=b+kn.
If c-d=mn, then c=d+mn.
ac-bd = (b+kn)(d+mn)-bd
= bd+bmn+dkn+kmn^2-bd
= bmn+dkn+kmn^2
= n(bm+dk+kmn)
So the integer t such that (ac)-(bd)=tn is bm+dk+kmn.
Therefore, .
//