We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.

We know that formula for permutations is given as

On substituting the given values in the formula we get,


Therefore, there are 39270 ways in which prizes can be awarded.
Answer:
D.
Step-by-step explanation:
Each toss is independent so the probability of getting a tail is the same thE OF GETTING A HEAD - 50%^.
Answer:
12 days
Step-by-step explanation:
420/35 to find amount of days to finish book
420/35 = 12
I am not going to tell you the answer but i can tell you how to find it out. First you have to put 19/38 on a paper. Then multipy the numarator and denomanator by the same number on the top and bottom which is called a whole number. 19/38 times 2/2 or 3/3 or 4/4 or anything. Your answer is equivalent to 19/38
Hello!
First you find the common difference in the sequence
6 - 12 = -6
0 - 6 = -6
The common difference is -6
We can now make the equation
-6(n - 1) + 12
we got the 12 because it is the first number in the sequence
Simplify
-6n + 6 + 12
Simplify
18 - 6n
The answer is B) an = 18 - 6n
Hope this helps!