Can someone tutor me too!!!
Θ
=
arcsin
(
.7
4.2
)
≈
10
∘
Explanation:
We view the ramp as a right triangle. The hypotenuse is 4.2 and the vertical side .7, which is opposite the angle
θ
we seek.
sin
θ
=
.7
4.2
=
1
6
I'm going to finish the problem but I'll note if we were actually building the ramp we don't need to know the angle; this sine is sufficient.
θ
=
arcsin
(
1
6
)
θ
≈
10
∘
which I think is a pretty steep ramp for a wheelchair.
There will be another inverse sine that is the supplementary angle, around
170
∘
, but we can rule that out as a value for a ramp wedge angle.
Answer:
7.22 feet
Step-by-step explanation:
From the question,
s = d/t................. Equation 1
Where s = speed of the space shuttle, d = distance traveled by the shuttle in an hour, t = time taken to travel the distance
make d the subject of the equation,
d = s×t.................... Equation 2
Given: s = 2.6×10000 feet per seconds, t = 1 hour = 3.6×1000 seconds.
Substitute these values into equation 2
d = (2.6×10000)/(3.6×1000)
d = 26000/3600
d = 7.22 feet.
Hence the shuttle travels 7.22 feet in an hour
Answer:
1125 times bigger
Step-by-step explanation:
