Answer:
Explanation:
<u />
<u>1. First find the density of your chain</u>
- Volume = displaced water volume
= Volume of Final level of water - initial level of water
= 20 ml - 15 ml = 5 ml
- Density = 66.7g / 5 ml = 13.34 g/ml
<u />
<u>2. Second, write the denisty of the chain as the weighted average of the densities of the other metals:</u>
Mass of gold × density of gold + mass of other metals × density of other metals, all divided by the mass of the chain.
Calling x the amount of gold, then the amount of other metals is 66.7 - x:
Then, there are 26.47 grams of gold in 66.7 grams of chain, which yields a percentage of:
- (26.47 / 66.7) × 100 = 39.7%
Answer:
The large sample n = 1713.96
Step-by-step explanation:
<u>Explanation</u>:-
given the population proportion was estimated to be 0.22
population proportion (P) = 0.22
The 95 % level of significance = 1.96≅ 2
The margin of error = 0.02
The formula of margin error
… ( i )
Substitute 'p' values in equation (1)
cross multiplication and simplification, we get
squaring on both sides, we get
the large sample n = 1713.96
The answer would be <span>v ≥ 5. ^-^ Glad I could help. </span>
A)
<h3>
The sample mean is 52</h3><h3>
The claimed population mean is 44</h3>
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The sample mean is the mean found in the survey (of the sample of people). The sample mean is found by adding up the values and dividing by the sample size n. The larger n gets, the closer the sample mean should get to the population mean. This is assuming the sample is random and representative of the population.
The population mean is a claim made by another study/survey/etc. Usually generalized statements such as "Americans spent an average of X dollars (in year Y)" would have X be considered the population mean.
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B)
<h3>Sample mean is 3.42</h3><h3>Claimed population mean is 3.56</h3>
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Same idea as part A, but we're using different numbers and a different problem context.
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Note: The year numbers and the sample sizes are not used to answer any of the four questions above.