Answer:
7.328m/s
Explanation:
Given parameters:
height of table = 0.68m
final velocity of the ball = 6m/s
Unknown:
Initial velocity of ball = ?
Solution:
To solve this problem, we are going to employ the appropriate motion equation.
We must understand that this fall occurs in the presence of gravity;
V = U + 2gH
Where;
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
H is the height of the pool table
Since U is the unknown, let us make it the subject of the expression;
U = V - 2gH
U = 6 - (2 x 9.8 x 0.68) = 7.328m/s(deceleration)
<span>A gymnast with mass m1 = 43 kg is on a balance beam that sits on (but is not attached to) two supports. The beam has a mass m2 = 115 kg and length L = 5 m. Each support is 1/3 of the way from each end. Initially the gymnast stands at the left end of the beam.
1)What is the force the left support exerts on the beam?
2)What is the force the right support exerts on the beam?
3)How much extra mass could the gymnast hold before the beam begins to tip?
Now the gymnast (not holding any additional mass) walks directly above the right support.
4)What is the force the left support exerts on the beam?
5)What is the force the right support exerts on the beam?</span>
Answer:
E1 = 10.15 * 10^4 N/C
E2 = 0
E3 = 10.15 *10^4 N/C
Explanation:
Given data:
Two 13 cm-long thin glass rods ( L ) = 0.13 m
charge (Q) = +11nC
distance between thin glass rods = 4 cm .
<u>Calculate the electric field strengths </u>
electric charge due to a single glass rod in the question ( E ) =
equation 1 can be used to determine E1, E2 and E3 because the points lie within the two rods hence the net electric field produced will be equal to the difference in electric fields produced
applying equation 1 to determine E1
E1 = ( distance from 1 rod is 0.01 m and from the other rod is 0.03 )
=
= 10.15 * 10^4 N/C
applying equation 1 to determine E2
E2 =
therefore E2 = 0
E1 = E3
hence E3 = 10.15*10^4 N/C
Answer:
B
Explanation:
the exact and absolute age of a rock layer