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Svetradugi [14.3K]
3 years ago
5

When an element tends to lose its valence electrons in chemical reactions, it behaves more like a

Physics
2 answers:
dimulka [17.4K]3 years ago
8 0

metal. i take the same course

Sloan [31]3 years ago
4 0
Electron toxic reaction dills with death

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Calculate the acceleration of a bottle rocket that is traveling at a speed of 74 m/s, and then descends at a speed of 89 m/s. It
Harlamova29_29 [7]

Answer:Falling objects form an interesting class of motion problems. For example, we can estimate the depth of a vertical mine shaft by dropping a rock into it and listening for the rock to hit the bottom. By applying the kinematics developed so far to falling objects, we can examine some interesting situations and learn much about gravity in the process.

Explanation:

5 0
3 years ago
A pressure vessel that has a volume of 10m3 is used to store high-pressure air for operating a supersonic wind tunnel. If the ai
Anna71 [15]

Answer:

The mass of air stored in the vessel is 235.34 kilograms.

Explanation:

Let supossed that air inside pressure vessel is an ideal gas, The density of the air (\rho), measured in kilograms per cubic meter, is defined by following equation:

\rho = \frac{P\cdot M}{R_{u}\cdot T} (1)

Where:

P - Pressure, measured in kilopascals.

M - Molar mass, measured in kilomoles per kilogram.

R_{u} - Ideal gas constant, measured in kilopascal-cubic meters per kilomole-Kelvin.

T - Temperature, measured in Kelvin.

If we know that P = 2026.5\,kPa, M = 28.965\,\frac{kg}{kmol}, R_{u} = 8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K} and T = 300\,K, then the density of air is:

\rho = \frac{(2026.5\,kPa)\cdot \left(28.965\,\frac{kg}{kmol} \right)}{\left(8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K} \right)\cdot (300\,K)}

\rho = 23.534\,\frac{kg}{m^{3}}

The mass of air stored in the vessel is derived from definition of density. That is:

m = \rho \cdot V (2)

Where m is the mass, measured in kilograms.

If we know that \rho = 23.534\,\frac{kg}{m^{3}} and V = 10\,m^{3}, then the mass of air stored in the vessel is:

m = \left(23.534\,\frac{kg}{m^{3}} \right)\cdot (10\,m^{3})

m = 235.34\,kg

The mass of air stored in the vessel is 235.34 kilograms.

7 0
3 years ago
FOR FLVS STUDENTS ONLY///NO BIT LINKS, SCAM LINKS, OR GIBBERSH
Marysya12 [62]

Answer:

whats thw question tho

Explanation:

6 0
3 years ago
The coefficient of static friction between a book and the level surface it slides on is 0.65. If the mass of the book is 0.2 kg,
just olya [345]

Answer: 1.274 N minimum force required to slide the book across the surface

Explanation:

Mass of the book = m = 0.2 kg

Normal force acting on the book,N = mg

Coefficient of friction =mu_s = 0.65

Minimum force required to slide the book across the surface= F

F=\mu_s\times N

F=0.65\times 0.2 kg\times 9.8 m/s^2=1.274 N

1.274 N minimum force required to slide the book across the surface

7 0
3 years ago
Read 2 more answers
A spaceship travels at a constant speed from earth to a planet orbiting another star. When the spacecraft arrives, 12 years have
tigry1 [53]

Answer:

7.2878\times10^{16} m

Explanation:

Time elapsed on Earth d_{t}= 12 years

Time elapsed on board the shipd_{t_o} = 9.2 years

now r= \frac{d_{t} }{d_t_o}= 12/9.2= 1.3043

v= c \sqrt{1-\frac{1}{r^2}}

v= 3\times10^8 \sqrt{1-\frac{1}{1.3043^2}}

v= 1.9258\times10^8

therefore distance L=  d_{t}\times v

putting value we get

=12\times\times1.9258\times10^8

=12\times\times365\times24\times3600\times1.9258\times10^8

= 7.2878\times10^{16} m

4 0
3 years ago
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