Ask question

Ask question

All categories

3 years ago

11

A worker drives a 0.554 kg spike into a rail tie with a 2.30 kg sledgehammer. The hammer hits the spike with a speed of 62.7 m/s

. If one fourth of the hammer’s kinetic energy is converted to the internal energy of the hammer and spike, how much does the total internal energy increase? Answer in units of J.

2 answers:

Goryan [66]3 years ago

8 0

Answer:

Increase in total energy will be equal to the increase in the internal energy i.e $1130.246$ Joules

Explanation:

Given

Weight of sledge hammer $= 2.30$ kilogram

Speed of sledge hammer $= 62.7$ meter per second

Kinetic energy is equal to half the product of mass and velocity square

$K E = \frac{1}{2} mv^2$

Substituting the value of mass and velocity, we get -

$KE = 0.5 * 2.30 * 62.7^2\\KE = 4520.9835$

It is given that one fourth of the energy is converted into internal energy

One fourth of kinetic energy is equal to

$\frac{1}{4} * 4520.9835\\= 1130.246$

Increase in total energy will be equal to the increase in the internal energy i.e $1130.246$ Joules

san4es73 [151]3 years ago

8 0

Answer:

The total internal increases energy is 1506.9 J.

Explanation:

Given that,

Mass of spike = 0.554 kg

Mass of sledgehammer.= 2.30 kg

Speed = 62.7 m/s

One-third of the kinetic energy of the hammer is converted into the internal energy.

We need to calculate the total internal energy increase

Using given relation of kinetic energy and internal energy

$E=\dfrac{K.E}{3}$

Where, E = internal energy

K.E = kinetic energy

Put the value into the formula

$E=\dfrac{1}{2\times3}\times2.30\times(62.7)^2$

$E=1506.9\ J$

Hence, The total internal increases energy is 1506.9 J.

You might be interested in

A closed box is filled with dry ice at a temperature of -87.1°C, while the outside temperature is 17.6°C. The box is cubical, me

natta225 [31]

Answer:

K=24.17 x 10⁻² J s⁻¹c⁻¹m⁻¹

Explanation:

Rate of flow of heat through a material is given by the following expression

$\frac{Q}{t} =\frac{KA\delta T}{d}$

where Q is amount of heat flowing in time t through area A and a medium of thickness d having two faces at temperature difference δT . K is thermal conductivity of the medium .

Here Q = 3.34 x 10⁶/6 , t = 24 x 60 x 60 = 86400 s , A = .332 X .332 = .0110224 m² , δT = 104.7

Put these values here

$\frac{3.34\times10^6}{6\times86400}= \frac{k\times.011224\times104.7}{4.41\times10^{-2}}$

$K=\frac{3.34\times4.41\times10^4}{6\times86400\times.011224\times104.7}$

K=24.17 x 10⁻² J s⁻¹c⁻¹m⁻¹

4 0

3 years ago

What is the average speed between the times t = 4s and t = 12 s?

ziro4ka [17]

You need distance and time to find average speed.

3 0

3 years ago

The energy an object possesses due to its form and position is know as

zvonat [6]

I believe the energy being described is the potential energy. Potential energy is the stored energy, it is the energy an object has because of its position or shape. It is also the energy possessed by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors. The major types of energy include the gravitational energy of an object that depends on its mass and its distance from the center of mass.

5 0

4 years ago

In this problem you will consider the balance of thermal energy radiated and absorbed by a person.Assume that the person is wear

Viefleur [7K]

Answer: $P=14.6 W$

Explanation:

According to the Stefan-Boltzmann law for real radiating bodies:

$P=\sigma A \epsilon T^{4}$ (1)

Where:

$P$ is the energy radiated (in Watts)

$\sigma=5.67(10)^{-8}\frac{W}{m^{2} K^{4}}$ is the Stefan-Boltzmann's constant.

$A$ is the Surface area of the body

$T=30\°C + 273.15= 303.15 K$ is the effective temperature of the body (its surface absolute temperature) in Kelvin

$\epsilon=0.6$ is the body's emissivity

On the other hand, we are told the human body is roughly approximated to a cylinder of length $L=2.0m$ and circumference $C=0.8m$ .

The circumference of a circle is: $C=0.8m=2 \pi r$ where $r$ is the radius. Hence $r=\frac{0.8m}{2 \pi}=0.1273 m$ .

Now we have to input this value for $r$ in the Area of a cylinder formula:

$A=\pi r^{2}L$

$A=\pi (0.1273 m)^{2}(2 m)$

$A=0.0509 m^{2}$ (2)

Substituting (2) in (1):

$P=(5.67(10)^{-8}\frac{W}{m^{2} K^{4}}) (0.0509 m^{2}) (0.6) (303.15 K)^{4}$ (3)

Finally:

$P=14.62 W \approx 14.6 W$

5 0

3 years ago

Light from a laser strikes a diffraction grating that has 5500 lines per centimeter. The central and first-order maxima are sepa

WINSTONCH [101]

.Answer:

491.4 nm

Explanation:

The distance between central and first maxima is,

$y=0.455m$

And the distance between screen abnd grating is,

$L=1.62 m$

Now the angle can be find as,

$tan\theta=\frac{y}{L} \\\theta=tan^{-1}(\frac{0.455}{1.62}) \\\theta=15.68^{\circ}$

Now the grating distance is,

$d=\frac{1}{5500} cm\\d=1.82\times 10^{-6}m$

Now with m=1 condition will become,

$\lambda=dsin\theta$

So,

$\lambda=1.82\times 10^{-6}m\times sin(15.68^{\circ})\\\lambda=1.82\times 10^{-6}m\times 0.270\\\lambda=491.4\times 10^{-9}m\\\lambda=491.4 nm$

Therefore the wavelength of laser light is 491.4 nm.

3 0

3 years ago