The number of different dinner combinations for each student that are possible is 24
<h3>How many different dinner combinations for each student are possible?</h3>
The given parameters are:
Entree choices = 3
Side dish = 4
Beverage = 2
The number of different dinner combinations for each student that are possible is
Combination = Entree * Side dish * Beverage
This gives
Combination = 3 * 4 * 2
Evaluate
Combination = 24
Hence, the number of different dinner combinations for each student that are possible is 24
Read more about combination at:
brainly.com/question/11732255
#SPJ1
Answer:
21:18
Step-by-step explanation:
Answer:
-4
Step-by-step explanation:
ok negative times negative = positive
and factors of 24 are
1,2,3,4,6,8,12,24
4 x 6 are the two consecutive EVEN numbers
so turn it to negative
-4 x -6 = 24
The largest is -4
You find the area of a triangle by using 1/2*b*h where b is the base and h is the height. since we already know the area is 20 and the height is for you plus them in so the problem would be 20= 1/2 (b) (4) then you multiply what you know together to get 20= 2b and then isolate the b by dividing both sides by two so the base should be 10 m
