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3 years ago

I don’t understand, please help! Solve m=p/2-n for n.

Mathematics

1 answer:

belka [17]3 years ago

6 0

Answer: n=p/2-m

Step-by-step explanation:

m=p/2-n (1)

Add n to both sides of the equation (1)

m+n=p/2-n+n => m+n=p/2 (2)

Subtract m from both sides of the equation (2)

m-m+n=p/2-m => n=p/2-m

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2logx=3-2log(x+3) solve for x

AVprozaik [17]

Answer:

$\large\boxed{x=\dfrac{-3+\sqrt{40+10\sqrt{10}}}{2}}$

Step-by-step explanation:

$2\log x=3-2\log(x+3)\\\\Domain:\ x>0\ \wedge\ x+3>0\to x>-3\\\\D:x>0\\============================\\2\log x=3-2\log(x+3)\qquad\text{add}\ 2\log(x+3)\ \text{to both sides}\\\\2\log x+2\log(x+3)=3\qquad\text{divide both sides by 2}\\\\\log x+\log(x+3)=\dfrac{3}{2}\qquad\text{use}\ \log_ab+\log_ac=\log_a(bc)\\\\\log\bigg(x(x+3)\bigg)=\dfrac{3}{2}\qquad\text{use the de}\text{finition of a logarithm}\\\\x(x+3)=10^\frac{3}{2}\qquad\text{use the distributive property}$

$x^2+3x=10^{1\frac{1}{2}}\\\\x^2+3x=10^{1+\frac{1}{2}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\x^2+3x=10\cdot10^\frac{1}{2}\qquad\text{use}\ \sqrt[n]{a}=a^\frac{1}{n}\\\\x^2+3x=10\sqrt{10}\qquad\text{subtract}\ 10\sqrt{10}\ \text{from both sides}\\\\x^2+3x-10\sqrt{10}=0\\\\\text{Use the quadratic formula}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\a=1,\ b=3,\ c=-10\sqrt{10}\\\\b^2-4ac=3^2-4(1)(-10\sqrt{10})=9+40\sqrt{10}\\\\x=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2(1)}=\dfrac{-3\pm\sqrt{40+10\sqrt{10}}}{2}\\\\x=\dfrac{-3-\sqrt{10+10\sqrt{10}}}{2}\notin D$

6 0

2 years ago

Find the geometric mean of the pair of numbers

Svetach [21]

Answer: a. 55

Step-by-step explanation:

The formula to find the geometeric mean between two numbers a and b is given by :-

$G.M. =\sqrt{ab}$

The given numbers are : 275 and 11

The geometric mean of 275 and 11 is given by :-

$G.M.=\sqrt{275\times11}\\\\\Rightarrow\ G.M. =\sqrt{3025}\\\\\Rightarrow\ G.M.=\sqrt{55\times55}\\\\\Rightarrow\ G.M.=\sqrt{55^2}\\\\\Rightarrow\ G.M.=55$

Hence, the geometric mean of 275 and 11 is 55.

So , the correct option is a. 55 .

4 0

2 years ago

Y is greater than or equal to 3and less than 7

In-s [12.5K]

Answer:

7 > y ≥ 3

Step-by-step explanation:

5 0

3 years ago

Hello I need help with number 10 and number 9

zimovet [89]

Answer:

-x - 3

Step-by-step explanation:

7 0

2 years ago

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The lifespans of gorillas in a particular zoo are normally distributed. The average gorilla lives 16 years; the

STatiana [176]

Using the Emperical rule:

68% lie with one one standard deviation:

16 + 1.7 , 16-1.7 = 17.7, 14.3

14.3 is part of the 68%.

The remaining 32% of the distribution is outside the range, with half being less than and half being greater than.

32/2 = 16

The probability of living loner than 14.3 Would be 16%

3 0

2 years ago