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vichka [17]
3 years ago
13

You practice your basketball shots every day. On Friday you made 20 shots. On Saturday you made 16 shots. What is the percent de

crease in shots you made?
4%


16%


20%


80%
Mathematics
2 answers:
STatiana [176]3 years ago
8 0
So,

All you have to do to find the percent decrease is to subtract your score on Saturday from your score on Friday and divide the result by your score on Friday.  If you let "f" represent your score on Friday and let "s" represent your score on Saturday, you can re-write this mathematically:

\frac{f - s}{f} = percent\ decrease

Substitute.
\frac{20 - 16}{20} = percent\ decrease
\frac{4}{20} \ or\  \frac{1}{5}\ or\ twenty\ percent = percent\ decrease

The percent decrease in shots you made was 20%.  That would be option C.
Tems11 [23]3 years ago
8 0

the percent decrease was 20% because 4 shots less were on sat.

put it into a fraction to find the percentage:

4/20

=20%

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timofeeve [1]

Answer:

answer b

step - by - step explanation

  1. Hotel A. per night charge is 64 $
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3 years ago
Is 1/10 closer to 0 or 1/2 ?
olchik [2.2K]

Answer:

its much closer to 0

Step-by-step explanation:

1/2 is more 5/10 and 0 is 0/10

0 is one away from one and 5 is 4 away

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3 years ago
1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6
meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

<u>2x-2y=-6     </u>

<u>7x        =-21</u>

x= -3

Putting value of x in equation 1  

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

Let

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right] = A  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = X  and  \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]= B

Then AX= B

or X= A⁻¹ B

where  A⁻¹= adj A/ ║A║   where mod A≠ 0

adj A=  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]   \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14     \left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc}42\\0\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-3\\0\\\end{array}\right]

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0
3 years ago
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galben [10]

Answer:

-4

Step-by-step explanation:

This looks like point-slope form, which I find personally hideous. Let's change it to slope-intercept form to ease my conscience. (remember that slope-intercept form is y=mx+b, where m=slope and b=y-intercept!)

y - 5 = -4(x-8)

y - 5 = -4x + 32

y = -4x + 37

It's in slope-intercept form now! And -4 looks to be our m.

<u>So the slope is -4.</u>

4 0
4 years ago
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The range of 3, 5, 1, 2, 4, 6, 0, 2 is *
Scrat [10]

Answer:

6-0=6

Step-by-step explanation:

you take the highest number subtract the lowest answer

6 0
3 years ago
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