Question

Solve the inequality e=" \frac{x+1}{x-8} \leq 0 " alt=" \frac{x+1}{x-8} \leq 0 " align="absmiddle" class="latex-formula">

Answer 1

$D:x\not=8\\ \frac{x+1}{x-8}\leq0\\ (x+1)(x-8)\leq0\\ x\in\langle-1,8\rangle\\\\ x\in\langle-1,8\rangle \wedge x\not=8\\ \boxed{x\in\langle-1,8)}$