3 years ago

Solve the inequality

e=" \frac{x+1}{x-8} \leq 0 " alt=" \frac{x+1}{x-8} \leq 0 " align="absmiddle" class="latex-formula">

1 answer:

5 0

$D:x\not=8\\
\frac{x+1}{x-8}\leq0\\
(x+1)(x-8)\leq0\\
x\in\langle-1,8\rangle\\\\
x\in\langle-1,8\rangle \wedge x\not=8\\
\boxed{x\in\langle-1,8)}
$

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