<u>Answer:</u> The correct option is d) 460 kJ
<u>Explanation:</u>
We are given:
Content of fat in energy drink = 2.0 g
Content of protein in energy drink = 6.0 g
Content of carbohydrate in energy drink = 16.3 g
Also,
The fuel value of fat = 38 kJ/g
The fuel value of protein = 17 kJ/g
The fuel value of carbohydrate = 17 kJ/g
So, the fuel value of the energy drink will be:
Total fuel value = 
Total fuel value = ![[76+102+277]=460kJ](https://tex.z-dn.net/?f=%5B76%2B102%2B277%5D%3D460kJ)
Hence, the correct option is d) 460 kJ
The answer is A. Aluminum Chloride it does not have the prefix "tri-" since it is ionic.
The mole fraction of a gaseous compound is equal to the ratio of the vapor pressure of the compound to the total pressure of the vessel. In this case, teh vapor pressure of tehe non-electrolyte is 760 - 745 = 15 mmHg. hence the mole fraction is 15 mm Hg / 760 mmHg equal to 0.0197
Answer:
Double replacement
Precipitation reaction
Explanation:
You have the reaction:
REACTANTS PRODUCTS
BaCl₂ (aq) + Na₂SO₄ (aq) ⇒ 2NaCl (aq) + BaSO₄(s)
The general form of a double replacement reaction is the following:
AB + CD ⇒ CD + AB
The reactants basically, exchanged partners. In the case of your problem, Barium(Ba) and Sodium(Na) switched places. So this makes it a double-replacement reaction.
Now how do I know it is a precipitation reaction. A precipitation reaction occurs when two solutions combine and salt is formed. Salt is solid, so how do I know that's what occured? Look at your equation again:
BaCl₂ (aq) + Na₂SO₄ (aq) ⇒ 2NaCl (aq) + BaSO₄(s)
aq means aqueous (liquid)
s means solid
If you look at the product formed in the reaction, from two solutions, it formed a solid. So this is your clue as to why it is a precipitation reaction.
Explanation:
Reduction is a chemical reaction in which electrons are gained by one of the atoms taking part in the reaction and lowering of an oxidation state of that atom.
Reduction takes place at the cathode.
In aqueous, vanadium(V) is present in +5 oxidation state which on reduction changes to vanadium(I) with +1 oxidation state.
The half reaction is :
