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inysia [295]
3 years ago
11

__________ force is the force of attraction and repulsion between subatomic particles.

Chemistry
1 answer:
SpyIntel [72]3 years ago
4 0
A.) Electrical force is your answer......
You might be interested in
What’a the answer!!?
Svetradugi [14.3K]

Answer:

2,1,2

1,2,1,1

the answer

3 0
3 years ago
A balloon of air now occupies 5.0 L, at 25 celcius and 1.00 atm. What temperature was it initially, if it occupied 4.0 L and was
xenn [34]

Answer: A. 219K

Explanation:

Using the Combined Gas Law; P1 V1/T1 = P2V2/T2

Where P1 = 0.92 atm, P2 = 1.00 atm

           V1 =4.0 L,   V2 = 5.0 L

           T1 =  ?,  T2 = 25 celcius = 298K

We therefore make T1 the subject of the formular;

T1 = P1 . V1 .T2 / P2. V2

    = 0.92atm x 4.0L x 298K / 1.00 atm x 5.0 L

    = 1096.64 /   5

    = 219.328 approx  219K

5 0
4 years ago
A different brand of iron tablet was analysed by Hitration with 0.0093 mol.L" potassium
Gre4nikov [31]

The concentration of iron used in the titration : 0.009 M

<h3>Further explanation</h3>

Given

Reaction

Cr₂O₇²⁻ + 6Fe²⁺ + 14H⁺ ⇒ 2Cr³⁺ + 6Fe³⁺ + 7H₂O

0.0093 mol/L potassium  dichromate

200 cm³ of dilute acid, 25cm³   was used in the titration.

Required

the concentration of iron

Solution

Titration formula

C₁V₁n₁=C₂V₂n₂⇒ From equation : n₁=6n₂(1=Cr₂O₇, 2=Fe)

titration average : 33+32.05+32.15+32.1 / 4 = 32.325 cm³(ml)

25 cm³ of iron solution used in titration :

\tt V_1=32.325~ml\\\\V_2=25~ml\\\\C_1=0.0093~M\\\\\\\\C_1.V_1.n_2=C_2.V_2.n_1\\\\0.0093\times 32.325\times 6=C_2\times 25\times 1\\\\C_2=0.07215~M

Dilution(25 ml from 200 ml iron solution)

\tt C_2.V_2=C_1.V_1\\\\0.007215\times 25=C_1\times 200\\\\C_1=0.009~M

4 0
3 years ago
An oxide of aluminum contains 0.545 g of Al and 0.485 g of O. Find the empirical formula
uysha [10]

Answer:

The answer is: <u>Al2O3</u>

Explanation:

The data they give us is:

  • 0.545 gr Al
  • 0.485 gr O.

To find the empirical formula without knowing the grams of the compound, we find it per mole:

  • 0.545 g Al * 1 mol Al / 27 g Al = 0.02 mol Al
  • 0.485 g O * 1 mol O / 16 g O = 0.03 mol O

Then we must divide the results obtained by the lowest result, which in this case is 0.02:

  • 0.02 mol Al / 0.02 = 1  Al
  • 0.03 mol O / 0.02 = 1.5  O

Since both numbers have to give an integer, multiply by 2 until both remain integers:

  • 1Al * 2 = 2Al
  • 1.5O * 2 = 3O

Now the answer is given correctly:

  • Al2O3

8 0
3 years ago
Which of the elements shown will not form ions, and why will they not do so?
grigory [225]

No elements visible!

Ions form between metals and non-metals.

Hope this helps!

6 0
2 years ago
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