One peanut M&M weighs approximately 2.33 g.
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Answer:
q1..no.2 and 4 are aromatic
<u>Answer:</u> The theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
....(1)
- <u>For Iron:</u>
Given mass of iron = 4.31 g
Molar mass of iron = 53.85 g/mol
Putting values in above equation, we get:
For the given chemical reaction:
By Stoichiometry of the reaction:
2 moles of iron produces 2 moles of iron (ii) oxide.
So, 0.0771 moles of iron will produce = of iron (ii) oxide
Now, calculating the theoretical yield of iron (ii) oxide using equation 1, we get:
Moles of of iron (II) oxide = 0.0771 moles
Molar mass of iron (II) oxide = 71.844 g/mol
Putting values in equation 1, we get:
To calculate the percentage yield of iron (ii) oxide, we use the equation:
Experimental yield of iron (ii) oxide = 5.17 g
Theoretical yield of iron (ii) oxide = 5.53 g
Putting values in above equation, we get:
Hence, the theoretical yield of iron (II) oxide is 5.53g and percent yield of the reaction is 93.49 %
Answer : Both solutions contain molecules.
Explanation : The number of molecules of 0.5 M of sucrose is equal to the number of molecules in 0.5 M of glucose. Both solutions contain molecules.
Avogadro's Number is =
which represents particles per mole and particles may be typically molecules, atoms, ions, electrons, etc.
Here, only molarity values are given; where molarity is a measurement of concentration in terms of moles of the solute per liter of solvent.
Since each substance has the same concentration, 0.5 M, each will have the same number of molecules present per liter of solution.
Addition of molar mass for individual substance is not needed. As if both are considered in 1 Liter they would have same moles which is 0.5.
We can calculate the number of molecules for each;
Number of molecules = ;
∴ Number of molecules = which will be =
Thus, these solutions compare to each other in that they have not only the same concentration, but they will have the same number of solvated sugar molecules. But the mass of glucose dissolved will be less than the mass of sucrose.