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Doss [256]
3 years ago
15

One peanut M&M weighs approximately 2.33 g.

Chemistry
1 answer:
Sphinxa [80]3 years ago
3 0

Answer:

There are 23076 peanut M&M's in 53.768 kg of M&M's.

Explanation:

First we <u>convert 53.768 kg into g</u>:

  • 53.768 kg * 1000 = 53768 g

Then we <u>divide the total mass of M&M's by the mass of one peanut M&M,</u> in order to calculate the answer:

  • 53768 g / 2.33 g = 23076

So there are 23076 peanut M&M's in 53.768 kg of M&M's.

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A new penny has a mass of 2.49 grams and occupies 0.349 cm cubed. If pure copper has a density of 8.96 g/cm cubed, is the new pe
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Answer: The new penny is not pure copper

Explanation:

Density \rho is defined as a relation between the mass m and the volume V:

\rho=\frac{m}{V}

Now, we are told the density of pure copper is:

\rho_{copper}=8.96 g/cm^{3}

And we are given the mass and volume of the new penny, with which we can calculate its density:

\rho_{penny}=\frac{m_{penny}}{V_{penny}}=\frac{2.49 g}{0.349 cm^{3}}

\rho_{penny}=7.13 g/cm^{3} As we can see the density of this penny is not equal to the density of pure copper, hence the new penny is not pure copper.

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How many moles are in 6.3x1054 molecules of Ca(C2H202)2?
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8 0
3 years ago
PLEASE HELP
swat32

Answer:

1461.7 g of AgI

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:

From the balanced equation above,

1 mole of CaI₂ reacted to produce 2 moles of AgI.

Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI

Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:

Mole of AgI = 6.22 moles

Molar mass of AgI = 108 + 127

= 235 g/mol

Mass of AgI =?

Mass = mole × molar mass

Mass of AgI = 6.22 × 235

Mass of AgI = 1461.7 g

Therefore, 1461.7 g of AgI were obtained from the reaction.

5 0
4 years ago
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