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cricket20 [7]
3 years ago
6

Which of the following would remain a liquid longer as temperature continues to drop?

Chemistry
2 answers:
Len [333]3 years ago
8 0

Answer:

Octane

Explanation:

Hydrocarbons are composed of carbon and hydrogen atoms and are generally non-polar. The only intermolecular force of attraction between hydrocarbons is the weak van der waals interaction. Longer the hydrocarbon chain, stronger will be this interaction.

In the given options:

Propane = C3H8

Octane = C8H18

Hexane = C6H14

Ethane = C2H6

Thus, octane is has the longest chain and will have the strongest van der waal interaction which will allow the molecule to stay in a liquid state longer.

viktelen [127]3 years ago
3 0

I just took a test with this question and got the answer wrong for saying ethane. The correct answer is propane.

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Does the hydrogen molecule obey the octet rule?
Alja [10]

Explanation:

Hydrogen does not obey the octet rule. Boron does not always

obey the octet rule and in fact forms Lewis acids such as BF3 which

only has 6 electrons.

6 0
3 years ago
HELPPP PLS
photoshop1234 [79]
I think it could be C maybeee though
6 0
3 years ago
A solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water. The molar mass of Cu is 63.55 g/mol the molar mass of S
slamgirl [31]

The molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.

<h3>How to calculate molarity?</h3>

The molarity of a solution can be calculated using the following formula:

Molarity = no of moles/volume

According to this question, a solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water.

no.of moles of CuSO4 = 35g ÷ 159.6g/mol

no. of moles of CuSO4 = 0.22 moles

Therefore; molarity of CuSO4 solution is calculated as follows:

M = 0.22 ÷ 0.25

M = 0.88M

Therefore, the molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.

Learn more about molarity at: brainly.com/question/12127540

6 0
2 years ago
A self-contained underwater breathing apparatus (SCUBA) uses canisters containing potassium superoxide. The superoxide consumes
emmainna [20.7K]

Answer:

52.0004 grams of mass of potassium superoxide  is required

Explanation:

Let moles carbon dioxide gas be n at 22.0 °C and 767 mm Hg occupying 8.90 L of volume.

Pressure of the gas,P = 767 mm Hg = 0.9971 atm

Temperature of the gas,T = 22.0 °C = 295.15 K

Using an ideal gas equation to calculate the number of moles.

PV=nRT

n=\frac{0.9971 atm\times 8.90 L}{0.0821 atm L/mol K\times 295.15 K}

n = 0.3662 mol

4KO_2(s)+2CO_2(g)\rightarrow 2K_2CO_3(s)+3O_2(g)

According to reaction, 2 moles of carbon-dioxide reacts with 4 moles of potassium superoxide.

Then 0.3662 mol of  of carbon-dioxide will react with:

\frac{4}{2}\times 0.3662 mol=0.7324 mol of potassium superoxide.

Mass of 0.7324 mol potassium superoxide:

0.7324 mol × 71 g/mol = 52.0004 g

52.0004 grams of mass of potassium superoxide is required.

8 0
3 years ago
What is the mass of 0.75 moles of (NH4)3PO4?
Tomtit [17]

Answer:

well it turns into N3H12PO4

Explanation:

8 0
3 years ago
Read 2 more answers
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