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cricket20 [7]
3 years ago
6

Which of the following would remain a liquid longer as temperature continues to drop?

Chemistry
2 answers:
Len [333]3 years ago
8 0

Answer:

Octane

Explanation:

Hydrocarbons are composed of carbon and hydrogen atoms and are generally non-polar. The only intermolecular force of attraction between hydrocarbons is the weak van der waals interaction. Longer the hydrocarbon chain, stronger will be this interaction.

In the given options:

Propane = C3H8

Octane = C8H18

Hexane = C6H14

Ethane = C2H6

Thus, octane is has the longest chain and will have the strongest van der waal interaction which will allow the molecule to stay in a liquid state longer.

viktelen [127]3 years ago
3 0

I just took a test with this question and got the answer wrong for saying ethane. The correct answer is propane.

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Use calc to determine whether it is possible to remove 99.99% Cu2 by converting it to Cu(s) in a solution mixture containing 0.1
inessss [21]

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it is possible to remove 99.99% Cu2 by converting it to Cu(s)

Explanation:

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Cu2+ + 2e- <--------------------------------------------------------------> Cu (s) Eo= 0.339 V

Sn2+ + 2e- <---------------------------------------------------------------> Sn (s) Eo= -0.141 V

In order to convert 99.99% Cu2 into Cu(s), the equation of reaction given below is needed:

Cu²⁺ + Sn ----------------------------------------------------------------------------> Cu + Sn²⁺.

Therefore, E°[overall] = 0.339 - [-0.141] = 0.48 V.

Therefore, the change in Gibbs' free energy, ΔG° = - nFE°. Where E° = O.48V, n= 2 and F = 96500 C.

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7 0
3 years ago
If the pressure on a gas sample is tripled and the absolute temperature is quadrupled, by what factor will the volume of the sam
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Answer:

b. 4/3

Explanation:

Given data

  • Initial pressure: P₁
  • Initial volume: V₁
  • Initial temperature: T₁
  • Final pressure: P₂ = 3 P₁
  • Final volume: V₂
  • Final temperature: T₂ = 4 T₁

We can find by what factor will the volume of the sample change using the combined gas law.

\frac{P_{1}.V_{1}}{T_{1}} =\frac{P_{2}.V_{2}}{T_{2}}\\\frac{P_{1}.V_{1}}{T_{1}} =\frac{3P_{1}.V_{2}}{4T_{1}}\\V_{1} =\frac{3V_{2}}{4}\\V_{2}=4/3 V_{1}

7 0
3 years ago
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