Answer:
1.27 x 10⁻⁴M
Explanation:
For a 2 to 1 ionization ratio, solubility in pure water can be calculated using the formula S = ∛(Ksp/27) = ∛(5.61 x 10⁻¹¹/27 = 1.27 x 10⁻⁴M.
Mg(OH)₂ ⇄ Mg⁺² + 2OH⁻ => Ksp = [Mg⁺²][OH⁻]² = (x)(2x)² = 4x³
Solve for 'x' => x = Solubility = ∛Ksp/4
Answer:- Specific gravity of glucose solution is 1.02.
Solution:- Specific gravity is the ratio of the compound density with water density, means how denser the compound solution is as compared to water.
specific gravity = 
density of glucose is given as 1.02 g per mL and water density is 1.00 g per mL.
Let's plug in the values in the formula:
specific gravity =
= 1.02
So, the specific gravity of glucose is 1.02. It indicates that glucose is 1.02 times more denser than water.