
If x²-1 is a factor of the polynomial, both x-1 and x+1 are factors of it.
According to the remainder theorem, if a binomial x-a is a factor of a polynomial p(x), then p(a)=0.
If x-1 and x+1 are factors of the polynomial p(x)=ax⁴+bx³+cx²+dx+e, then p(1)=0 and p(-1)=0.
Answer:
<h3>
ln (e^2 + 1) - (e+ 1)</h3>
Step-by-step explanation:
Given f(x) = ln and g(x) = e^x + 1 to get f(g(2))-g(f(e)), we need to first find the composite function f(g(x)) and g(f(x)).
For f(g(x));
f(g(x)) = f(e^x + 1)
substitute x for e^x + 1 in f(x)
f(g(x)) = ln (e^x + 1)
f(g(2)) = ln (e^2 + 1)
For g(f(x));
g(f(x)) = g(ln x)
substitute x for ln x in g(x)
g(f(x)) = e^lnx + 1
g(f(x)) = x+1
g(f(e)) = e+1
f(g(2))-g(f(e)) = ln (e^2 + 1) - (e+ 1)
Answer:
1. 3.
Step-by-step explanation:
The answer to tx2x365 is 730t so when you solve the others you also get 730t
Answer:
x = 110°
Step-by-step explanation:
The sum of the interior angles of a polygon is
sum = 180° (n - 2) ← n is the number of sides
Here n = 6, thus
sum = 180° × 4 = 720°
Sum the given angles and equate to 720
125 + x + 130 + 90 + 165 + 100 = 720, that is
610 + x = 720 ( subtract 610 from both sides )
x = 110°
Answer:
C
Step-by-step explanation:
Brief explanation
The Sample space represented by 40 students are considered a larger sample size. Consequently, even with the decreasing number of population remaining doing the exam, the distribution of x is approximately normal