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Rufina [12.5K]
2 years ago
9

A hard drive that is running slowly may not have been properly.

Mathematics
1 answer:
leonid [27]2 years ago
4 0
I'm sorry, but I'm a bit confused on what you're trying to ask. Could you please clarify? 
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Given equation x = 6 + i, w = -1 + 5i and z = 4 - 8i, determine each of the following in the form of a + bi
Temka [501]

Answer:

i) 28 - 30i

ii) 36 + 28i

Step-by-step explanation:

i) x = 6 + i ⇒2x = 2(6 + i) = 12 + 2i

z = 4 - 8i ⇒ 4z = 4(4 - 8i) = 16 - 32i

2x + 4z = (12 + 2i) + (16 - 32i) = 28 - 30i

ii) w = -1 + 5i and z = 4 - 8i

w × z = (-1 + 5i)(4 - 8i) = -4 + 8i + 20i - 40i^{2}⇒collect like terms

w × z = -4 + 28i - 40i^{2}

∵ i^{2}=-1

∴w × z = -4 + 28i - 40(-1) = -4 + 28i + 40 = 36 + 28i

3 0
2 years ago
Wha are the equations. of the asymptotes of the graph of the function f(x)=3x^2-2x-1/x^2+3x+10
Leviafan [203]
The asymptote is the line the graph comes close to but never touches, so if you graph it out you should be able to see it! Sorry I couldn't help any more but good luck

3 0
3 years ago
Given: \overline{AC} \perp \overline{BD} AC ⊥ BD and \overline{BD} BD bisects \overline{AC}. AC . Prove: \triangle ABD \cong \tr
Fofino [41]

Answer:

The Proof for

△ABD ≅ △CBD is below

Step-by-step explanation:

Given:

\overline{AC} \perp \overline{BD}

\overline{BD} \ bisects\  \overline{AC}

AD = CD      .........BD bisect AC

To Prove:

△ABD ≅ △CBD

Proof:

In  ΔABD  and ΔCBD  

BD ≅ BD              ....……….{Reflexive Property}

∠ADB ≅ ∠CDB    …………..{Measure of each angle is 90°( \overline{AC} \perp \overline{BD} )}

AD ≅ CD              ....……….{ \overline{BD} \ bisects\  \overline{AC} }

ΔABD  ≅ ΔCBD   .......….{By Side-Angle-Side Congruence test}  ...Proved

4 0
3 years ago
What do you do if the divisor (the number you're dividing
Annette [7]

Answer:

you can use decimals

Step-by-step explanation:

7 0
3 years ago
A private jet can fly 1,095 miles in 3 hours with a tailwind but only 987 miles in 3 hours into a headwind find the speed of the
Verizon [17]

Answer:

The speed of the jet is 347 mph and the  speed of the wind is 18 mph.

Step-by-step explanation:

We have the following:

x = the speed of the jet in still air.

y = the speed of the wind

we know that the speed is equal to:

v = d / t

therefore the distance would be:

d = v * t

if we replace with the information of the exercise we have:

3 * (x + y) = 1095

3 * (x - y) = 987

we must solve this system of equations, add both equations and we are left:

3 * x + 3 * y = 1095

3 * x - 3 * y = 987

3 * x + 3 * y + 3 * x - 3 * y = 1095 + 987

6 * x = 2082

x = 2082/6 = 347

now to calculate y, we replace:

3 * (347 + y) = 1095

1041 + 3 * y = 1095

3 * y = 1095 - 1041

y = 54/3 = 18

The speed of the jet is 347 mph and the  speed of the wind is 18 mph.

8 0
3 years ago
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