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prisoha [69]
4 years ago
13

which two tools below would be the most useful in testing how the mass of an object can affect the distance it moves after being

pushed
Physics
1 answer:
Mariulka [41]4 years ago
3 0
It would be best to list the answer choice

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Will binoculars work properly if their prisms (assume n = 1.50) are immersed in water (nwater= 1.33)? assume that binoculars wor
Amanda [17]

The binoculars will not work properly.

Please refer to the diagram attached.

Binoculars work on the principle of total internal reflection. The incident ray from air enters the prism through on face normally and it strikes the opposite face at an angle of 45°. The ray undergoes Total internal reflection if its critical angle is less than the angle of incidence,which , in this case is 45°.

The critical anglei_{c} is related to the refractive index of the material of glass μ as shown below.

\mu =\frac{1}{sini_c}

For a refractive index equal to 1.5, the critical angle is found as shown below.

sini_c=\frac{1}{\mu} \\ =\frac{1}{1.5} \\ =0.666

Take the inverse of the value 0.666 to determine the critical angle.

sin^{-1} (0.666)=41.8^o

The critical angle in air is less than the angle of incidence, and hence total internal reflection occurs in air.

When the binoculars are immersed in water, the ray passes into the glass through water. therefore, the refractive index of the prism when immersed in water is given by,

\mu_g_w=\frac{\mu_g}{\mu_w}

Therefore the critical angle <em>c</em> in this case is given by,

sinc=\frac{\mu_w}{\mu_g}

Substitute 1.33 for \mu_w and 1.5 for \mu_g.

sinc=\frac{\mu_w}{\mu_g} \\ =\frac{1.33}{1.5} \\ =0.8866

Take the inverse of the value 0.8866.

c=sin^{-1} (0.8866)\\ =62^o

Since the critical angle of the prism when immersed in water, is 62°, which is greater than the angle of incidence of 45° required for viewing the object, the binoculars which are set for Total reflection in air, will not function when immersed in water.

4 0
4 years ago
The object experiences two external forces: 60 N to the west and 130 N to the east. What is the net external force?
MArishka [77]

Answer: 70 N to the East

Explanation:

lets assume east is positive and west is negative, since they are in opposite directions the net external force = F1+F2

Net force = (-60) + 130

Net force = 70

or

Net force = 70 N in the east direction

4 0
3 years ago
What is the mass of a person who weighs 653 N at earths surface
miss Akunina [59]

Answer:

66.6 kg

Explanation:

The weight of a person at Earth's surface is given by

W=mg

where

m is the mass of the person

g=9.8 m/s^2 is the acceleration of gravity

The person in the problem has a weight of

W = 653 N

Therefore, we can rearrange the equation to find his mass:

m=\frac{W}{g}=\frac{653}{9.8}=66.6 kg

7 0
4 years ago
Please help as fast you can
Ilya [14]

Answer:

d a

Explanation:

7 0
3 years ago
a train traveling at 30m/s comes to a complete stop in 20 sec.how far did the train go during the deceleration
elixir [45]

Answer:

600m

Explanation:

v=30m/s

t=20s

s=VT

20×30=600m

3 0
3 years ago
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