<span>Well, light gathering capacity of a telescope is dependent upon the area of aperture</span>
Answer:
The fluids speed at a)
and b)
are
and
respectively
c) Th volume of water the pipe discharges is:
Explanation:
To solve a) and b) we should use flow continuity for ideal fluids:
(1)
With Q the flux of water, but Q is
using this on (1) we have:
(2)
With A the cross sectional areas and v the velocities of the fluid.
a) Here, we use that point 2 has a cross-sectional area equal to
, so now we can solve (2) for
:

b) Here we use point 2 as
:

c) Here we need to know that in this case the flow is the volume of water that passes a cross-sectional area per unit time, this is
, so we can write:
, solving for V:

Answer:
3.99*10^-3N/C
Explanation:
Using
Ep= kq/r²
Where r = 0.6mm = 0.6*10^-3m
K= 8.9*10^9 and q= 1.6*10^-19
So = 8.9*10^9 * 1.6*10^-19/0.6*10^-3)²
= 3.99*10^-3N/C
It [the diamond] would act like a prism, and make a rainbow, or, the light would break up and disappear
Hope I helped!
~Mathlete12321
To approve to people that the Catholic Church was wrong but they threatened Galileo and he stop