Answer:
i have never done an expirament
Explanation:
I can help you draw the ray diagram.
F = m . g = 76.5 x 9..8 = 749.7
Net Force = 3225 - 749.7 = 2475.3
F = m.a
2475.3 = 76.5 a
a = 32.35
V = at + v1
V = at + 0
V = 32.35 x 0.15
V = 4.8525
Hope this helps
Answer:
107.3 m/s
Explanation:
The motion of Garlit is a uniformly accelerated motion (=constant acceleration), therefore we can use the following suvat equation:
![v=u+at](https://tex.z-dn.net/?f=v%3Du%2Bat)
where
u is the initial velocity
v is the final velocity
a is the acceleration
t is the time
In this problem, we have:
u = 0 (Garlit starts from rest)
is the acceleration
Therefore, the final velocity after t = 6.5 s is:
![v=0+(16.5)(6.5)=107.3 m/s](https://tex.z-dn.net/?f=v%3D0%2B%2816.5%29%286.5%29%3D107.3%20m%2Fs)
Answer:
The second material's index of refraction is 1.17.
Explanation:
Given that,
Refractive index of the material, n = 1.29
Critical angle is 65.9 degrees.
We need to find the second material's index of refraction. We know that at critical angle of incidence, angle of refraction is equal to 90 degrees. Using Snell's law as:
![n_1\sin \theta_c=n_2\sin (90)\\\\n_2=n_1\sin \theta_c\\\\n_2=1.29\times \sin (65.9)\\\\n_2=1.17](https://tex.z-dn.net/?f=n_1%5Csin%20%5Ctheta_c%3Dn_2%5Csin%20%2890%29%5C%5C%5C%5Cn_2%3Dn_1%5Csin%20%5Ctheta_c%5C%5C%5C%5Cn_2%3D1.29%5Ctimes%20%5Csin%20%2865.9%29%5C%5C%5C%5Cn_2%3D1.17)
So, the second material's index of refraction is 1.17.