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barxatty [35]
3 years ago
7

Which of the following statements correctly describe the various forms of EM radiation listed above?A) They have different wavel

engths.B) They have different frequencies.C) They propagate at different speeds through a vacuum depending on their frequency.D) They propagate at different speeds through nonvacuum media depending on both their frequency and the material in which they travel.E) They require different media to propagate.
Physics
1 answer:
Aleksandr [31]3 years ago
5 0

Answer: A and B

Explanation:

Electromagnetic radiations are examples of electromagnetic waves with increasing frequency and decreasing wavelength in the following order radiowaves - infrared waves - visible lights - ultraviolet rays- x-rays - gamma rays.

They did not require material medium for their propagation.

The statement above shows that EM radiations possesses different wavelengths and frequency.

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Dominic made the table below to organize his notes about mixtures. A 1-column table. The first column labeled properties of mixt
MA_775_DIABLO [31]

Answer:

The is: Although it is possible to have more than one state, it is also possible to have only one state.

Explanation:

Hope this helps! ;-)

3 0
4 years ago
What is the total net charge of an atom that contains 13 protons and 10 electrons? *
umka2103 [35]

Answer:

It should be *+3

Explanation:

Al3+ indicates an ion of aluminum having a charge of + 3. I.e., since an aluminum atom normally has 13 protons and 13 electrons, this ion has 10 electrons (-10 charge) and 13 protons (+ 13 charge) giving it a charge of + 3 (-10 + 13 = +3).

The other i.d.i.ot answered unhelpfully

4 0
3 years ago
Alejandro Kirk is the catcher for the Blue Jays’ baseball team. He exerts a forward force on the 0.145-kg baseball to bring it t
lozanna [386]

The kinematics and Newton's second law allow to find the results for the questions about the motion of the ball are:

  • The acceleration is: a = 5.4 10³ m / s²
  • The force is: F = 7.84 10² N

Given parameters

  • Mass of the ball m = 0.145 kg
  • Ball starts speed vo = 38.2 m / s
  • Setback distance x = 0.135 m

To find

  • Acceleration
  • The force

Kinematics studies the movement of bodies, looking for relationships between the position, speed and acceleration of bodies.

         v² = v₀² - 2 ax

Wher vo es la initial veloicity, a the acceleration y x is the distance,

When the ball stops the velocity is zero.

         0 = v₀² - 2ax

         a = \frac{v_o^2}{2x}  

Let's calculate

         a = \frac{38.2^2}{2 \ 0.135}  

         a = 5.4 10³ m / s²

Newton's second law establishes a relationship between force, mass, and acceleration of the body.

             F = ma

             F = 0.145 5.4 10³

             F = 7.84 10² N

In conclusion using kinematics and Newton's second law we can find the results for the questions about the motion of the ball are:

  • The acceleration is: a = 5.4 10³ m / s²
  • The force is: F = 7.84 10² N

Learn more here: brainly.com/question/13536532

7 0
3 years ago
Armando is the CEO for a successful large business. He wants to create a visual aid to represent the relationships between diffe
Butoxors [25]
The Answer Is: An Organizational Chart.
3 0
3 years ago
Read 2 more answers
Suppose the two carts have the same mass m. In the initial state, these two carts are moving toward each other with the same ini
statuscvo [17]

Answer:

in all three cases the total moment is zero

cases A and B the kinetic energy is conserved.  

In case C the velocity decreases so the kinetic energy decreases

Explanation:

This is a momentum conservation exercise

          p = mv

In order for the moment to be preserved, we must define a system formed by the two cars, so that the forces during coke have been internal.

Before crash

car 1      p₀₁ = m v₀

car 2     p₀₂ = - mv₀

pose us several situations, we analyze each one

A) After the crash the cars stop

      p_{f} = 0

p₀₁      m v₀

p₀₂    -m v₀

p_{f}  0

B) After the collision, each vehicle reverses its direction

       

p₀₁            m v₀

p₀₂           -m v₀

p_{f1}       -m v₀

p_{f2}       m v₀

C) In this case some of the kinetic energy is lost which is converted into internal energy, for example, deformation, heat, friction.

Consequently the speed of the cars is

               v < v₀

p₀₁          m v₀

p₀₂         - m v₀

p_{f1}     -m v

p_{f2}    m v

D) in cases A and B the momentum is maintained, but in case C the total momentum is maintained, even when the speed of the cars decreases, this is pf_total = 0

In all cases the total impulse is zero

           p₀ = p₀₁ + p₀₂ = m v₀ - mv₀

           p₀_total = 0

in all three cases the total moment is zero

E) The total kinetic energy is the sum of the kinetic energy of each car

          K_total = K₀₁ + K₀₂

          K_total = ½ m v₀² + ½ m (-v₀)²

          K_total = m v₀²

we see that because it is squared, the sign of the velocity does not matter, therefore in cases A and B the kinetic energy is conserved.

In case C the velocity decreases so the kinetic energy decreases

         Kf_total < K₀_total

the missing energy is transformed into internal energy during sackcloth.

In the attachment we can see a vector diagram of the momentum in each case

7 0
4 years ago
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