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3 years ago

The object experiences two external forces: 60 N to the west and 130 N to the east. What is the net external force?

Physics

1 answer:

MArishka [77]3 years ago

4 0

Answer: 70 N to the East

Explanation:

lets assume east is positive and west is negative, since they are in opposite directions the net external force = F1+F2

Net force = (-60) + 130

Net force = 70

Net force = 70 N in the east direction

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When a certain element is excited with electricity, we see three main lines in its emission spectrum: two red lines and one oran

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The absorption spectrum would have all the wavelengths of the light source but would have black lines where the two red and one orange lines were in the emission spectrum

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4 years ago

When the liquid line is restricted, the supply of refrigerant to the metering device is reduced. What is the effect on suction p

Nimfa-mama [501]

Answer:

The suction pressure decreases and the superheat increases when the liquid line is restricted and the supply of refrigerant to the metering device is reduced.

Explanation:

1. The five components of refrigeration are:

Fluid refrigerant
Compressor
Condenser coil
Evaporator coil
Expansion device.

The compressor limits the vapor released by the refrigerant. This

causes a rise in pressure (in refrigerant), which then pushes the

vapor into the coils on the outside of the refrigerator.

2. Now when the cooler air meets the warm gas present in the coils, it

gets converted into liquid form.

3. Thus, when the liquid form is at high pressure, the refrigerant then

cools down as it flows through the coils placed in the fridge ( in both

freezing and normal sections).

4. The refrigerant also absorbs the warm air present in the fridge, which

causes it to evaporate and flow back through the compressor and the

cycle repeats in the same form.

Thus, when the liquid line is restricted and the supply of refrigerant to the metering device is reduced it causes a decrease in suction pressure and an increase in superheat.

Learn more about refrigeration here:

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8 0

2 years ago

An object accelerates from rest and travels 53 m west in 5.2 s. Determine the acceleration

zmey [24]

Answer:

20.4m/s²

Explanation:

Given parameters:

Initial velocity = 0m/s

Distance = 53m

Time = 5.2s

Unknown:

Acceleration = ?

Solution:

This is a linear motion and we use the right motion equation;

S = ut + $\frac{1}{2}$ at²

S is the distance

u is the initial velocity

a is the acceleration

t is the time

Insert the parameters and solve;

53 = (0x 5.2) + $\frac{1}{2}$ x a x 5.2

53 = 2.6a

a = $\frac{53}{2.6}$ = 20.4m/s²

6 0

3 years ago

A 16.2 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The

S_A_V [24]

To solve this problem we will apply the concepts related to the balance of forces. We will decompose the forces in the vertical and horizontal sense, and at the same time, we will perform summation of torques to eliminate some variables and obtain a system of equations that allow us to obtain the angle.

The forces in the vertical direction would be,

$\sum F_x = 0$

$f-N_w = 0$

$N_w = f$

The forces in the horizontal direction would be,

$\sum F_y = 0$

$N_f -W =0$

$N_f = W$

The sum of Torques at equilibrium,

$\sum \tau = 0$

$Wdcos\theta - N_wLsin\theta = 0$

$WdCos\theta = fLSin\theta$

$f = \frac{Wd}{Ltan\theta}$

The maximum friction force would be equivalent to the coefficient of friction by the person, but at the same time to the expression previously found, therefore

$f_{max} = \mu W=\frac{Wd}{Ltan\theta}$