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3 years ago

11

Emma bought 16 packages of rolls for a party.there were 12 rolls in a package. After the party there were 8 roll left over. How

many rolls were eaten.explain

2 answers:

Georgia [21]3 years ago

4 0

184 rolls were eaten. You multiply 16 and 12 and get 192. So that means there was 192 rolls altogether. Now you take 8 from 192 and you get 184.

TiliK225 [7]3 years ago

3 0

Well 16x12=192 then subtract it by 8 and 184 rolls were eaten! OMG

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The perimeter of a rectangle is 48 inches. The length of the rectangle is 3 times the width of the rectangle. What is the area o

Lilit [14]

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Step-by-step explanation:

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3 years ago

Evaluate 7P4<br> Evaluate 12C5

Verdich [7]

Answer:

Below.

Step-by-step explanation:

7P4

= 7! / (7-4)!

= 7*6*5*4*3*2*1 / ( 3*2*1)

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12C5

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5 0

2 years ago

A whale costs $14700 and depreciates in value by 8% per year. When will the whale be worth $100

sammy [17]

Answer:

x = 60

Step-by-step explanation:

The question is asking

$14,700 * (1 - 8%)^x = $100

$14,700 * (1 - 0.08)^x = $100

$14,700 * (0.92)^x = $100

(0.92)^x = $100/$14,700

log(0.92^x) = log($100/$14,700)

x * log(0.92) = log(0.0068027)

x = log(0.0068027)/log(0.92)

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3 0

2 years ago

in 2012, the population of a city was 63,000. by 2017, the population was reduced to approximately 54,100. identify any equation

Akimi4 [234]

Answer:

<em></em> $f(x) = 63000(0.97)^x$ <em></em>

<em></em>

Step-by-step explanation:

Given

$f(0) = 63000$ ---x = 0, in 2012

$f(5) = 54100$ -- x = 5, in 2017

Required

Select all possible equations

Because there is a reduction in the population, as time increases; the rate must be less than 1.

An exponential function is represented as:

$f(x) = ab^x$

Where

$b = rate$

rate > 1 in options (a) and (b) i.e. 1.03

This implies that (a) and (b) cannot be true

For option (c), we have:

$f(x) = 63000(0.97)^x$

Set x = 0

$f(0) = 63000(0.97)^0 = 63000*1=63000\\$

Set x = 5

$f(5) = 63000(0.97)^5 = 63000*0.8587=54098.1 \approx 54100$

<em>This is true because the calculated values of f(0) and f(5) correspond to the given values</em>

For option (d), we have:

$f(x) = 52477(0.97)^x$

Set x = 0

$f(0) = 52477(0.97)^0 - 52477* 1 = 52477$

<em>This is false because the calculated value of f(0) does not correspond to the given value</em>

For option (e), we have:

$f(x) = 63000(0.97)^\frac{1}{5x}$

Set x = 0

$f(0) = 63000(0.97)^\frac{1}{5*0} = 63000(0.97)^\frac{1}{0} =$ undefined

<em>This is false because the f(x) is not undefined at x = 0</em>

For option (f), we have:

$f(x) = 52477(0.97)^{5x$

Set x = 0

$f(0) = 52477(0.97)^{5*0} = 52477(0.97)^0 =52477*1= 52477$

<em>This is false because the calculated value of f(0) does not correspond to the given value</em>

<em>From the computations above, only (c) </em> $f(x) = 63000(0.97)^x$ <em> is true</em>

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2 years ago