3 years ago

2x-3x²=5 in standard formation

Mathematics

2 answers:

harina [27]3 years ago

5 0

Answer:

Step-by-step explanation:

1. Make the equation equal to zero

2x - 3x^2 = 5 = 0

2. Then apply simple algebra by subtracting -5 from +5

2x - 3x^2 = 5 = 0

-5

3. Now move the -5 to the left side of the equation

2x - 3x^2 -5 = 0

4. Now arrange the numbers into standard form (ax^2 + bx + c)

-3x^2 + 2x - 5

UkoKoshka [18]3 years ago

4 0

Bc 2x—x3=ew.r divorce

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2x-3x²=5 in standard formation​

2x-3x²=5 in standard formation