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svetoff [14.1K]
2 years ago
13

2x-3x²=5 in standard formation​

Mathematics
2 answers:
harina [27]2 years ago
5 0

Answer:

Step-by-step explanation:

1. Make the equation equal to zero

2x - 3x^2 = 5 = 0

2. Then apply simple algebra by subtracting -5 from +5

2x - 3x^2 = 5 = 0

                  -5

3. Now move the -5 to the left side of the equation

2x - 3x^2 -5 = 0

4. Now arrange the numbers into standard form (ax^2 + bx + c)

-3x^2 + 2x - 5

UkoKoshka [18]2 years ago
4 0
Bc 2x—x3=ew.r divorce
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