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4 years ago

PLEASE HELP LAST QUESTION The figure below shows triangle ABC on the coordinate plane.

Mathematics

2 answers:

Soloha48 [4]4 years ago

7 0

B is (0,1)
A is (4,-6)
C is (-2, -2)

vivado [14]4 years ago

5 0

Answer: A'(4,-6) , B'(0,1), C'(-2,-2)

Step-by-step explanation:

From the given graph the coordinates of ΔABC area A (2,-2), B(-2,5) and C(-4,2)

If a translation is applied on ΔABC two units to the right and four units down to create ΔA'B'C'.

Then to find the coordinates of ΔA'B'C' will be we need to apply the translation rule

$(x,y)\rightarrow(x+2,y-4)$

Now, $A(2,-2)\rightarrow A'(2+2,-2-4)=A'(4,-6)$

$B(-2,5)\rightarrow B'(-2+2,5-4)=B'(0,1)$

and $C(-4,2)\rightarrow C'(-4+2,2-4)=C'(-2,-2)$

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sattari [20]

They are traveling at right angles to each other so we can say one is traveling north to south and the other west to east. Then we can say that there positions, y and x are:

y=150-600t x=200-800t

By using the Pythagorean Theorem we can find the distance between these two planes as a function of time:

d^2=y^2+x^2, using y and x from above

d^2=(150-600t)^2+(200-800t)^2

d^2=22500-180000t+360000t^2+40000-320000t+640000t^2

d^2=1000000t^2-500000t+62500

d=√(1000000t^2-500000t+6250)

So the rate of change is the derivative of d

dd/dt=(1/2)(2000000t-500000)/√(1000000t^2-500000t+6250)

dd/dt=(1000000t-250000)/√(1000000t^2-500000t+6250)

So the rate depends upon t and is not a constant, so for the instantaneous rate you would plug in a specific value of t...

...

To find how much time the controller has to change the airplanes flight path, we only need to solve for when d=0, or even d^2=0...

1000000t^2-500000t+62500=0

6250(16t^2-8t+1)=0

6250(16^2-4t-4t+1)=0

6250(4t(4t-1)-1(4t-1))=0

6250(4t-1)(4t-1)=0

6250(4t-1)^2=0

4t-1=0

4t=1

t=1/4 hr

Well technically, the controller has t<1/4 because at t=1/4 impact will occur :)

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3 years ago

Which fraction is larger 6/17 or 18/51

fredd [130]

Answer:

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Step-by-step explanation:

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3 years ago

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Galina-37 [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Help me find the right angles URGENT !!

sasho [114]

Answer:

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3 years ago

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