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3 years ago

Match the trinomials with their factors.

Mathematics

2 answers:

yaroslaw [1]3 years ago

6 0

Thank you who asked the question because u made it simple to answer

Leviafan [203]3 years ago

4 0

(a-4)(a-5) goes with b
(a-10)(a-2) goes with d
(a-4)(a+5) goes with a
(a-10)(a+2) goes with c
e is not used.

if you want to check take the pairs and foil or box them out.

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Given that cos θ = –12∕13 and θ is in quadrant III, find csc θ.

Trava [24]

Answer:

Step-by-step explanation:

We are given:

$\displaystyle \cos(\theta)=-\frac{12}{13},\,\theta\in\text{QIII}$

Since cosine is the ratio of the adjacent side over the hypotenuse, this means that the opposite side is (we can ignore negatives for now):

$o=\sqrt{13^2-12^2}=\sqrt{25}=5$

So, the opposite side is 5, the adjacent side is 12, and the hypotenuse is 13.

And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.

Cosecant is given by the hypotenuse over the opposite side. Thus:

$\displaystyle \csc(\theta)=\frac{13}{5}$

Since θ is in QIII, cosecant must be negative:

$\displaystyle \csc(\theta)=-\frac{13}{5}$

Our answer is A.

7 0

2 years ago

Read 2 more answers

1. Kyle and John are twins who decided to plan an imaginary trip that started with cliff jumping. There were two different spots

Vikki [24]

Answer:

a) Δx = -35ft

b) Δx = -25ft

c) Kyle traveled 10ft more than John

Step-by-step explanation:

We define a coordinate reference system() in which y = 0 corresponds to the water surface.

a) The initial position of Kyle in our coordinate reference system is:

$x_{o} = 20 ft$

and his final position is:

$x_{f} = -15 ft$

Therefore, he traveled

Δx = $x_{f} - x_{o} = -15 - 20 = -35 ft$

b) The initial position of John in our coordinate reference system is:

$x_{o} = 15 ft$

and his final position is:

$x_{f} = -10 ft$

Therefore, he traveled

Δx = $x_{f} - x_{o} = -10 - 15 = -25 ft$

c) Then, Kyle traveled 10ft more than John

6 0

3 years ago

The difference of a number s and 6

Luda [366]

Answer:

idk

Step-by-step explanation:

What you do you have to find someone more smarter than me!

6 0

3 years ago

A man that is 6 feet tall is standing so that the tip of his shadow is 20 feet from a light pole. His shadow is 8 feet long. Wha

pychu [463]

Answer:

The answer to your question is: the height of the light pole is 15 ft.

Step-by-step explanation:

See the picture below

Now, we can do proportions to finds the height of the light pole

$\frac{20}{8} = \frac{x}{6}$

Solve for x

x = 6(20) / 8

x = 120 / 8

x = 15 ft

4 0

2 years ago

Graph ARST with vertices R(6, 6), S(3, -6), and T(0, 3) and its image after a

padilas [110]

Answer:

The answer is the second figure and the vertices of Δ R'S'T' are:

R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)

Step-by-step explanation:

* Lets revise some transformation

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) reflected across the line y = x

∴ Its image is (y , x)

- If point (x , y) reflected across the line y = -x

∴ Its image is (-y , -x)

- Now we can solve the problem

∵ R = (6 , 6) , S = (3 , -6) , T = (0 , 3), they are the vertices of ΔRST

- The triangle RST is reflected over the y-axis

- According to the rule above the signs of x-coordinates will change

∵ R = (6 , 6)

∴ Its image is (-6 , 6)

∵ S = (3 , -6)

∴ Its image is (-3 , -6)

∵ T = (0 , 3)

∴ Its image is (0 , 3)

* Now lets look to the figure to find the correct answers

- The image of Δ RST is ΔR'S'T'

∵ The vertices of the image of ΔRST are:

R' = (-6 , 6) , S' = (-3 , -6) , T' = (0 , 3)

* The answer is the second figure

7 0

3 years ago