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zimovet [89]
3 years ago
14

Find the length of the curve.

Mathematics
1 answer:
gulaghasi [49]3 years ago
3 0

Answer:

wag na natin balikan si ex kalimutan na natin yun

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A tree grows vertically on a hillside. The hill is at a 16° angle to the horizontal. The tree casts an 18-meter shadow up the hi
elixir [45]
The height of the tree is the sum of the part below the line parallel to the horizontal and the part above the line parallel to the horizontal.

Height of the part below the line parallel to the horizontal = 18 sin16° = 4.96 meters
Horizontal distance of the tip of the of the shadow from the tree = 18 cos16° = 17.30 meters
Height of the part above the line parallel to the horizontal = 17.3 tan68° = 42.83 meters

Height of the tree = 4.96 + 42.83 = 47.79 meters
8 0
3 years ago
What is the absolute value of 25? |25| = ?
Kryger [21]

Answer:

25, -25

Step-by-step explanation:

This is the answer. It's simple. Just think of the two lines next to the number and that can be -25 and 25.

3 0
4 years ago
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There are two rows of 8 chairs set up in the library for a puppetshow how many chairs are set up use the distributive property t
laila [671]
It there are 2 rows of 8 chairs all you have to do is add 8+8 which equals 16
Unless it means there are 8 chairs altogether split into 2 even rows then you do 8\2 =4

I would write down both answers if your not sure which one it is :)
7 0
3 years ago
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What is 84/6..............................
mixas84 [53]

Answer:

14

Step-by-step explanation:

8 0
3 years ago
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The polynomial P(x)=3x^3+2x^2-6x has _ local maxima and minima. Also please explain how to do it if you can.
liraira [26]
1.  Find the derivative of <span>P(x)=3x^3+2x^2-6x.  It's P'(x)=9x^2 + 4x - 6.
2.  Set this result equal to zero and solve for the critical values:
</span>             9x^2 + 4x - 6 = 0      Using the quadratic formula, I got
              x = [-4 plus or minus sqrt(232)] / 18.  Reducing this,
               x = [-4 plus or minus 2 sqrt(58)]; thus, there are two real, unequal roots and two real, unequal critical values.
3.   One at a time, examine the two critical values:  determine whether the derivative changes from neg to pos or from pos to neg at each of these values.  Example:  If the derivative is pos to the left of the first c. v. and neg to the right, we've got a local max.

4.  Since there are only 2 critical values, you can have no more than 1 local max (corresponding to a change in the sign of the derivative from pos to neg) and one local min.  (from neg to pos).

Message me if this explanation is not sufficient to help you understand this problem thoroughly.  
6 0
4 years ago
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