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Strike441 [17]
3 years ago
9

Use the diagram of ◾ABC to find m<DM<D=​

Mathematics
1 answer:
Yuliya22 [10]3 years ago
7 0

Answer:

In quadrilateral ABCD we have

AC = AD

and AB being the bisector of ∠A.

Now, in ΔABC and ΔABD,

AC = AD

[Given]

AB = AB

[Common]

∠CAB = ∠DAB [∴ AB bisects ∠CAD]

∴ Using SAS criteria, we have

ΔABC ≌ ΔABD.

∴ Corresponding parts of congruent triangles (c.p.c.t) are equal.

∴ BC = BD.

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Help me please i don't know what i'm doing please help
UNO [17]

Answer: -1/9

Step by step explanation:

The common difference of an arithmetic sequence can be found by picking 2 consecutive terms, and subtracting the second from the first. For example, if I chose the terms 2 and 1 8/9, I would find the common difference by:

1 8/9 - 2, which is equal to -1/9.

You can confirm this by picking another pair of consecutive terms. Let's pick 1 7/9 and 1 2/3:

1 2/3 - 1 7/9 = -1/9, as 1 2/3 = 1 6/9, so 1 6/9 - 1 7/9 = -1/9

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Step-by-step explanation:

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What’s the formula to -1/2,-3/10,-9/50,-27/250,....
laila [671]

Answer:

The formula is ⇒ \frac{-1}{2}(\frac{3}{5})^{n-1}

Step-by-step explanation:

∵ The sequence is -1/2 , -3/10 , -9/50 , -27/250

∵ (-3/10) ÷ (-1/2) = 3/5

∵ (-9/50) ÷ (-3/10) = 3/5

∴ It is a geometric sequence

∴ The formula is Tn = ar^(n - 1)

Where a is the first term , r is the constant ratio between each two consecutive terms and n is the position of the number

∴ Tn = -1/2 ( 3/5)^(n - 1)

∴ Tn= \frac{-1}{2}(\frac{3}{5})^{n-1}  

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3 years ago
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