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marishachu [46]
3 years ago
6

When vibrational motion in an object increases, which is a true statement?

Physics
2 answers:
Verdich [7]3 years ago
8 0

Answer:

The answer is A

Explanation:

zubka84 [21]3 years ago
6 0
A -..................................is the correct option
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A crumb of bread, of mass 0.056 kg, is pulled upon by ants from rival anthills. They exert the following forces: 0.06 N to the n
Valentin [98]

Answer:

a) 1.855m/s^2, 9.71\° to the east-north

b) 0.103N, 9.46° to the west-south

Explanation:

To find the acceleration of the system you can assume that  the forces are applied in a xy plane, where force toward north are directed in the +y direction, and forces to the east in the +x direction. BY taking into account the components of the acceleration for each axis you obtain the following systems of equations:

0.06N-0.06Nsin(45\°)=ma_y\\\\0.08N-0.02N+0.06cos(45\°)=ma_x

m: mass of the crumb of bread = 0.056kg

you simplify the equations an replace the values of the mass in order to obtain the acceleration components:

a_y=\frac{0.017N}{0.056kg}=0.313\frac{m}{s^2}\\\\a_x=\frac{0.102N}{0.056kg}=1.829\frac{m}{s^2}

\theta=tan^{-1}(\frac{0.313}{1.829})=9.71\°\\\\a=\sqrt{a_x^2+a_y^2}=\sqrt{(1.829)^2+(0.313)^2}\frac{m}{s^2}=1.855\frac{m}{s^2}

then, the acceleration of the system has a magnitude of 1.855m/s^2 and a direction of 9.71\° to the east-north

The fifth force must cancel both x an y components of the previous net force, that is:

0.06N-0.06Nsin(45\°)+F_y=0\\\\F_y=-0.017N\\\\0.08N-0.02N+0.06cos(45\°)+F_x=0\\\\F_x=-0.102N\\\\\phi=tan^{-1}(\frac{-0.017}{-0.102N})=9.46\°

F=\sqrt{(0.102)^2+(0.017)^2}N=0.103N

the, the force needed to reach the equilibrium has a magnitude of 0.103N and a direction of 9.46° to the west-south

4 0
3 years ago
Energy transferred as heat always moves from an object
nata0808 [166]
Well, if we are being technical, yes and the only reason I say yes is because the sun is a hot gas rock. And it gives off UV rays which is heat on earth. So, yes. It does
3 0
3 years ago
Covalent bonds ___ conduct electricity well. <br><br> Always <br> Usually<br> Rarely<br> Never
mr_godi [17]
They rarely conduct electricity well.
4 0
3 years ago
Read 2 more answers
Two charged objects separated by some distance attract each other. If the charges on both objects are doubled with no change in
Serggg [28]

Answer:

(a) The force between them quadruples

Explanation:

According to coulomb's law, initial force between the two charged objects is given as;

F_1=\frac{Kq_1q_2}{r^2}

where;

k is coulomb's constant

q₁ is the charge on the first object

q₂ is the charge on the second object

r is the distance between the two objects

When the charges on both objects are doubled, then;

q₁ = 2q₁

q₂ = 2q₂

Force between the two charged objects will become

F_2 = \frac{K2q_12q_2}{r^2} =  \frac{4Kq_1q_2}{r^2} = 4(\frac{Kq_1q_2}{r^2}) = 4F_1

Therefore, the force between them quadruples

4 0
3 years ago
A particle moves with acceleration function a(t) = 5 + 4t - 2t^2. Its initial velocity v(0) = 3 m/s and its initial displacement
eimsori [14]

Answer:

Its position after 4 seconds is 62 meters.

Explanation:

It is given that,

The acceleration of the particle is given by equation :

a(t)=5+4t-2t^2

Also, a=\dfrac{dv}{dt}

v=\int\limits {a.dt}

v=\int\limits {(5+4t-2t^2).dt}

v=5t+2t^2-\dfrac{2}{3}t^3+c

At t = 0, v(0)=3\ m/s. So, c = 3

v=5t+2t^2-\dfrac{2}{3}t^3+3

Also, v=\dfrac{ds}{dt}, s is the position

s=\int\limits {v.dt}

s=\int\limits {(5t+2t^2-\dfrac{2}{3}t^3+3).dt}

s=\dfrac{5}{2}t^2+\dfrac{2}{3}t^3-\dfrac{t^4}{6}+3t+c'

At t = 0, s(0)=10\ m. So, c' = 10

s=\dfrac{5}{2}t^2+\dfrac{2}{3}t^3-\dfrac{t^4}{6}+3t+10

At t = 4 s

s=\dfrac{5}{2}(4)^2+\dfrac{2}{3}(4)^3-\dfrac{(4)^4}{6}+3(4)+10

s = 62 m

So, at t = 4 seconds the position of the particle is 62 meters. Hence, this is the required solution.

5 0
3 years ago
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