4 for sure because you dont want anything spilling on you or others that is harmful.
Answer:
a} <u>Infrared radiant heaters.</u>
<u>b} Fan heaters.</u>
Explanation:
I hope this is okay, should I give more.
Answer:

Explanation:
Given that,
The magnitude of magnetic field, B = 0.55 T
The radus of the loop, r = 43 cm = 0.43 m
The current in the loop, I = 5.8 mA = 0.0058 A
We need to find the magnetic moment of the loop. It is given by the relation as follows :

Put all the values,

So, the magnetic moment of the loop is equal to
.
Answer:
B) 3.50 m/s
Explanation:
The linear velocity in a circular motion is defined as:

The angular frequency (
) is defined as 2π times the frequency and r is the radius, that is, the distance from the center of the circular motion.

Replacing (2) in (1):

We have to convert the frequency to Hz:

Finally, we calculate how fast is the child moving:
