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artcher [175]
2 years ago
9

Describe how the total mass of the particles before the reaction occurs compares to the total mass of the particles produced by

the reaction.
Physics
1 answer:
zzz [600]2 years ago
4 0
The law of conservation of mass says you don't create or destroy atoms in a reaction. So the total mass of reagents equals the total mass of the products.
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Choose the statement about Masters sports programs that is true.
likoan [24]
Pretty sure rhe answer to your question is A.
7 0
3 years ago
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Explain the theory of plate tectonics in your own words
Irina-Kira [14]
The outer rigid layer of the earth is divided into a couple of dozen “plates” that move around across earths surface relative to each other.
7 0
3 years ago
Gauss's Law states that the net electric flux, , through any closed surface is proportional to the charge enclosed: . The analog
Natali [406]

The analogous formula for magnetic fields is the Ampere's law.

To find the answer, we need to know about the Ampere's law of magnetism.

<h3>What's Ampere's law of magnetism?</h3>

Ampere's law states that the close line integral of magnetic field around a current carrying loop is directly proportional to the current enclosed within it.

<h3>What's is the mathematical expression of Ampere's law?</h3>

Mathematically, Ampere's law is

B•dl= μ₀I

Thus, we can conclude that the analogous formula for gauss law is the Ampere's law in magnetism.

Learn more about the Ampere's law here:

brainly.com/question/17070619

#SPJ4

5 0
2 years ago
In certain cases, using both the momentum principle and energy principle to analyze a system is useful, as they each can reveal
SpyIntel [72]

Answer:

A) F_g = 26284.48 N

B) v = 7404.18 m/s

C) E = 19.19 × 10^(10) J

Explanation:

We are given;

Mass of satellite; m = 3500 kg

Mass of the earth; M = 6 x 10²⁴ Kg

Earth circular orbit radius; R = 7.3 x 10⁶ m

A) Formula for the gravitational force is;

F_g = GmM/r²

Where G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²

Plugging in the relevant values, we have;

F_g = (6.67 × 10^(-11) × 3500 × 6 x 10²⁴)/(7.3 x 10⁶)²

F_g = 26284.48 N

B) From the momentum principle, we have that the gravitational force is equal to the centripetal force.

Thus;

GmM/r² = mv²/r

Making v th subject, we have;

v = √(GM/r)

Plugging in the relevant values;

v = √(6.67 × 10^(-11) × 6 x 10²⁴)/(7.3 x 10⁶))

v = 7404.18 m/s

C) From the energy principle, the minimum amount of work is given by;

E = (GmM/r) - ½mv²

Plugging in the relevant values;

E = [(6.67 × 10^(-11) × 3500 × 6 × 10²⁴)/(7.3 x 10⁶)] - (½ × 3500 × 7404.18)

E = 19.19 × 10^(10) J

5 0
3 years ago
Calculate the final velocity right after a 117 kg rugby player who is initially running at 7.45 m/s collides head‑on with a padd
Free_Kalibri [48]

Answer:

v_f = 0.87 m/s

Explanation:

We are given;

F_avg = -17700 N (negative because it's backward)

m = 117 kg

Δt = 5.50 × 10^(−2) s

v_i = 7.45 m/s

Now, formula for impulse is given by;

I = F•Δt = - 17700 x 5.50 × 10^(−2) = - 973.5 kg.m/s

From impulse momentum theory, we know that;

Change in momentum of particle is equal to impulse.

Thus,

Δp = I = m•v_f - m•v_i

Thus,

-973.5= 117(v_f - 7.45)

Thus,

-973.5/117 = (v_f - 7.45)

-8.3205 + 7.45 = v_f

v_f = - 0.87 m/s

We'll take absolute value as;

v_f = 0.87 m/s

5 0
3 years ago
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